In this subsection, we investigate the behavior of total cells (u-cell and v-cell).
Proof
First, model (7) can be arranged as
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\begin{document}
\begin{align*}
\begin{cases} \frac { { - z } { 2 }} U^ { \prime } ( z ) = U^ { \prime \prime } ( z ) - ( U^2 ( z ) + U ( z ) V ( Z ) ) ^ { \prime \prime } , \\ \frac { - z } { 2 } V^ { \prime } ( z ) = V^ { \prime \prime } ( z ) - ( V^2 ( z ) + U ( z ) V ( Z ) ) ^ { \prime \prime } . \end{cases} \tag { 9 }
\end{align*}
\end{document}
We combine two equations of system (9) as
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\begin{document}
\begin{align*}
\frac { - z } { 2 } ( U ( z ) + V ( z ) ) ^ { \prime } = ( U ( z
) + V ( z ) ) ^ { \prime \prime } - \left( ( U ( z ) + V ( z ) )
^2 \right) ^ { \prime \prime } .
\end{align*}
\end{document}
Let W(z) be U(z) + V(z). Thus, W(z) is
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\begin{document}$$ \frac { u ( x , t ) + v ( x , t ) } { T } $$\end{document}
, where z is
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\begin{document}$${x } \over { \sqrt { t }} $$\end{document}
. Then we obtain model (8). ▪
Following equation (8), we spread out the item (W2(z)″; then, equation (8) is shown as
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\begin{document}
\begin{align*}
( 2W ( z ) - 1 ) W^ { \prime \prime } ( z ) + 2 ( W^ { \prime } (
z ) ) ^2 = \frac { z } { 2 } W^ { \prime } ( z ) . \tag { 10 }
\end{align*}
\end{document}
Assuming W′(2W − 1) is not equal with zero, the above equation can be rewritten as
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\begin{document}
\begin{align*}
\frac { W^ { \prime \prime } ( z ) } { W^ { \prime } ( z ) } +
\frac { 2W^ { \prime } ( z ) } { 2W ( z ) - 1 } = \frac { z } {
2 } \cdot \frac { 1 } { 2W ( z ) - 1 } , \tag { 11 }
\end{align*}
\end{document}
dividing both sides of equation (10) by W′(2W − 1). For calculating conveniently, let
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\begin{document}$${ \overline W} ( z ) $$\end{document}
be
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\begin{document}$$W ( z ) - \frac { 1 } { 2 } $$\end{document}
, and replace the item W(z) in equation (11) by
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\begin{document}$$ {\overline{W }} ( z ) + \frac { 1 } { 2 } $$\end{document}
. Therefore, the equation
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\begin{document}
\begin{align*}
\frac {{\overline W } ^ { \prime \prime } ( z ) } {{\overline W }
^ {\prime} ( z )} + \frac {{\overline W } ^ { \prime } ( z ) }
{{\overline W } ( z ) } = \frac {z} {4W ( z )} \tag {12}
\end{align*}
\end{document}
is obtained trivially.
In order to obtain a homogeneous solution of equation (12), we consider this equation
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\begin{document}
\begin{align*}
\frac {{\overline W } ^ { \prime \prime } ( z ) } { {\overline W }
^ { \prime } ( z ) } + \frac {{\overline W } ^ { \prime } ( z ) }
{{ \overline W } ( z ) } = 0. \tag { 13 }
\end{align*}
\end{document}
By integrating the above equation with respect to z twice, a homogeneous solution of equation (12) is obtained as
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\begin{document}$${ \overline W} ( z ) = { \sqrt 2}{ \sqrt k_1z + k_2}$$\end{document}
, where k1 and k2 are constants, with the consequence that
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\begin{document}$$W ( z ) = \frac { 1 } { 2 } + { \sqrt 2 } { \sqrt k_1z + k_2 } $$\end{document}
is a homogeneous solution of equation (11), where k1 and k2 are constants. We assume
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\begin{document}$$W ( z ) = \frac { 1 } { 2 } + { \sqrt 2 } { \sqrt c_1z + c_2 } $$\end{document}
could be a solution of equation (11), where c1 and c2 are functions of z. Applying
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\begin{document}$$W ( z ) = \frac { 1 } { 2 } + { \sqrt 2 } { \sqrt c_1z + c_2 } $$\end{document}
to equation (11), we have
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\begin{document}
\begin{align*}
( { \sqrt c_1z + c_2 } ) ^ \frac { 1 } { 2 } ( { \sqrt c_1z + c_2
} ) ^ { \prime \prime } = \frac { z } { 4 { \sqrt 2 } } ( { \sqrt
c_1z + c_2 } ) ^ { \prime } , \tag { 14 }
\end{align*}
\end{document}
where c1 and c2 are functions of z.
Through analyzing equation (14) for some very small z, we can know the properties of the item c1z + c2 in equation (14) as z approaches zero. Furthermore, the properties of
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\begin{document}$$W ( z ) ( = \frac { 1 } { 2 } + { \sqrt 2 } \sqrt { c_1z + c_2 } ) $$\end{document}
can be gotten.
Now, according to the types of the functions (c1 and c2), we have three cases as follows:
(a) Given that c1 is a constant function and c2 not, then following equation (14),
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\begin{document}
\begin{align*}( c_1z + c_2 ) ^ \frac { 1 } { 2 } c^ { \prime \prime } _2 =
\frac { z } { 4 { \sqrt 2 } } ( c_1 + c_2^ { \prime } ) \sim 0 ,
\end{align*}
\end{document}
as z ∼ 0. Moreover,
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\begin{document}$$c_2 ( c_2^{ \prime \prime} ) ^2$$\end{document}
approaches zero as z approaches zero. Therefore, we know that c2 or
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\begin{document}$$c_2^{ \prime \prime}$$\end{document}
is close to zero when z is close to zero. Reasonably, we could assume that
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\begin{document}$$c_2 = \sum \nolimits^n_{m = 0 , m \ne 1}a_mz^m$$\end{document}
for all n ≥ 0 and n ≠ 0, or
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\begin{document}$$c_2 = \sum \nolimits^n_{m = 1}a_mz^m$$\end{document}
for all n ≥ 1. Hence, in this case, W(z) is near to
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\begin{document}$$ \frac { 1 } { 2 } + { \sqrt 2a_0 } $$\end{document}
or
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\begin{document}$$\frac {1} {2}$$\end{document}
as z is near to zero.
(b) Given that c2 is a constant function and c1 not, then following equation (14),
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\begin{document}
\begin{align*}
( c_1z + c_2 ) ^ \frac { 1 } { 2 } ( c_1^ { \prime \prime } z +
2c^ { \prime } _1 ) = \frac { z } { 4 { \sqrt 2 } } ( c_1^ {
\prime } z + c_1 ) \sim 0 ,
\end{align*}
\end{document}
as z ∼ 0. Moreover,
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\begin{document}$$c_2 ( c_1^{ \prime} ) ^2$$\end{document}
approaches zero as z approaches zero. Reasonably, we could assume that
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\begin{document}$$c_1 = \sum \nolimits_{m = 0 , m \ne 1}^na_mz^m$$\end{document}
for all n ≥ 0 and n ≠ 0. Hence, in this case, W(z) is near to
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\begin{document}$$ \frac { 1 } { 2 } + { \sqrt 2c_2 } $$\end{document}
as z is near to zero.
(c) Given that c1 and c2 are constant functions, then following equation (14),
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\begin{document}
\begin{align*}
( c_1z + c_2 ) ^ \frac { 1 } { 2 } ( c_1z + c_2 ) ^ { \prime
\prime } = \frac { z } { 4 { \sqrt 2 } } ( c_1z + c_2 ) ^ {
\prime } \sim 0 ,
\end{align*}
\end{document}
as z ∼ 0. Moreover,
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\begin{document}$$c_2 ( 2c_1 + c_2^{ \prime \prime} ) ^2$$\end{document}
approaches zero as z approaches zero. Reasonably, we could assume that
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\begin{document}$$c_1 = \sum \nolimits^n_{m = 1}a_mz^m$$\end{document}
and
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\begin{document}$$c_2 = \sum \nolimits^n_{m = 1}b_mz^m$$\end{document}
for all n ≥ 1. Hence, in this case, W(z) is near to
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\begin{document}$$ \frac { 1 } { 2 } $$\end{document}
as z is near to zero.
According to the results of case (a), (b), and (c), we have
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\begin{document}$$W ( z ) \le \frac { 1 } { 2 } + d$$\end{document}
, where d is a positive constant as z is near to zero. Recall that we set
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\begin{document}$$z = \frac { x } { { \sqrt t } } $$\end{document}
and let
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\begin{document}$$W ( z ) = U ( z ) + V ( z ) = \frac { u ( x , t ) } { T } + \frac { v ( x , t ) } { T } $$\end{document}
. In consequence, we find that the density of total cells will approach a constant when time is far into the future.
Furthermore, we can calculate a particular solution of equation (14) to verify that W(z) would be close to
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\begin{document}$$ \frac { 1 } { 2 } $$\end{document}
as z is close to zero.
Proof
Following equation (14), let c1z + c2 = ξ(z), where c1 and c2 are functions of z. Then
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\begin{document}
\begin{align*}
\frac { \xi^ { \prime \prime } ( z ) } { \xi^ { \prime } ( z ) }
= \frac { z } { 4 { \sqrt 2 } \sqrt { \xi ( z ) } } \tag { 15 }
\end{align*}
\end{document}
is obtained immediately.
Let ξ(z) = k3zr and apply ξ(z) to equation (15). We can compute r = 4 and
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\begin{document}$$k_3 = \frac { 1 } { 288 } $$\end{document}
. In consequence,
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\begin{document}$$ \xi ( z ) = \frac { z^4 } { 288 } $$\end{document}
is a particular solution of equation (14). Namely,
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\begin{document}$$ \sqrt { c_1z + c_2 } = \frac { z^2 } { 12 { \sqrt 2 } } $$\end{document}
. Consequently,
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\begin{document}$$W ( z ) = \frac { 1 } { 2 } + \frac { z^2 } { 12 { \sqrt 2 } } $$\end{document}
and
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\begin{document}$$W ( z ) \sim \frac { 1 } { 2 } $$\end{document}
as z ∼ 0.
Moreover, we get c1z + c2 = c3z4, where c3 is a function of z. Applying c3z4 to equation (14), we get
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\begin{document}$$c_3{ \sqrt c_3}$$\end{document}
approaches zero as z approaches zero. Reasonably, we could assume
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\begin{document}
\begin{align*}
c_3 = \sum_{m = 1}^n a_mz^m
\end{align*}
\end{document}
for all n ≥ 1 as z approaches zero. Therefore,
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\begin{document}$$c_1z + c_2 = z^4 \sum \nolimits^n_{m = 1}a_mz^m$$\end{document}
for all n ≥ 1 as z approaches zero, and
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\begin{document}$$W ( z ) = \frac { 1 } { 2 } + { \sqrt 2 } z^2 \big ( \sum \nolimits^n_ { m = 1 } a_mz^m \big) ^ \frac { 1 } { 2 } $$\end{document}
Recall that
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\begin{document}$$W ( z ) = \frac { u ( x , t ) } { T } + \frac { v ( x , t ) } { T } $$\end{document}
. In consequence, we know that the density of total cells will be close to
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\begin{document}$$\frac {T} {2}$$\end{document}
, where T is a constant and T ≥ u(x, t) + v(x, t) initially as time is far into the future. ▪
We can make use of the particular solution
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\begin{document}$$W ( z ) = \frac { 1 } { 2 } + { \sqrt 2 } z^2 \big( \sum \nolimits^n_ { m = 1 } a_mz^m \big) ^ \frac { 1 } { 2 } $$\end{document}
to analyze the properties of single cell population. Those processes will be shown in the next section.