3. The SCJD Model
In this section, we generalize the SCJ model to allow duplications.
A duplication operation on a genome,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Pi$$
\end{document}
, takes a linear chromosome, C, in
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Pi$$
\end{document}
and produces a new genome,
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$$\Pi^\prime$$
\end{document}
, with an additional copy of the chromosome. For example, if
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$$\Pi = \{ abcd , efg \} $$
\end{document}
, then a duplication of the first chromosome will give
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$$\Pi^\prime = \{ abcd , abcd , efg \} $$
\end{document}
. An SCJD operation is either an SCJ or a duplication.
Given two linear genomes on the same gene set of size n, an ordinary one,
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$$\Gamma$$
\end{document}
, and a duplicated one,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Delta$$
\end{document}
, a sequence of SCJD operations that transforms
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$$\Gamma$$
\end{document}
into
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Delta$$
\end{document}
is called an SCJD sorting scenario. The SCJD distance, denoted by
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$${d_{SCJD}} ( \Gamma , \Delta )$$
\end{document}
, is the number of operations in a shortest SCJD sorting scenario between
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$$\Gamma$$
\end{document}
and
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$$\Delta$$
\end{document}
.
Since we focus on linear genomes, we will assume from now on that all chromosomes, including intermediate ones, are linear unless specified otherwise. The following simple lemma shows that this can be satisfied when using only SCJ operations:
Lemma 1. A sequence of SCJ operations transforming one linear genome into another linear genome can be reordered, producing another sequence with the same length such that all intermediate genomes are linear.
Proof. Let
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Pi$$
\end{document}
and
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$$\Gamma$$
\end{document}
be two ordinary linear genomes and let
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$${o_1}, \ldots , {o_d}$$
\end{document}
be a sequence of SCJ operations transforming
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$$\Pi$$
\end{document}
into
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$$\Gamma$$
\end{document}
. Suppose there is a join operation, oi, which creates a circular chromosome C by joining its two telomeres, x and y. Since
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma$$
\end{document}
is linear, there is a cut operation oi for
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$$i < j$$
\end{document}
that breaks C into a linear chromosome by cutting an adjacency
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$$\{ w , z \} $$
\end{document}
. We create a new sequence of the same length by replacing oi with a cut of
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$$\{ w , z \} $$
\end{document}
and replacing oj with a join of x and y. In the new sequence, the chromosome C is linear. By repeating the argument for every intermediate circular chromosome, the lemma holds. ■
The examples below demonstrate SCJ double distances and SCJD sorting scenarios. For simplicity, we drop the braces around genomes from now on.
Example 1.
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$$\Gamma = a$$
\end{document}
,
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$$\Delta = a - a$$
\end{document}
;
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$$d{d_{SCJ}} ( \Gamma , \Delta ) = 1$$
\end{document}
;
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$${d_{SCJD}} ( \Gamma , \Delta ) = 2$$
\end{document}
:
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\begin{align*}
\Gamma \mathop \to \limits_{dup} a , a \mathop \to \limits_{join} \Delta
\end{align*}
\end{document}
Example 2.
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$$\Gamma = ab$$
\end{document}
,
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$$\Delta = ab,ab$$
\end{document}
;
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$$d{d_{SCJ}} ( \Gamma , \Delta ) = 0$$
\end{document}
;
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$${d_{SCJD}} ( \Gamma , \Delta ) = 1$$
\end{document}
:
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\begin{align*}
\Gamma \mathop \to \limits_{dup} \Delta
\end{align*}
\end{document}
Example 3.
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$$\Gamma = a , bc$$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Delta = ab,abcc$$
\end{document}
;
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$d{d_{SCJ}} ( \Gamma , \Delta ) = 4$$
\end{document}
;
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$${d_{SCJD}} ( \Gamma , \Delta ) \le 4$$
\end{document}
:
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\begin{align*}
\Gamma \mathop \to \limits_{join} abc \mathop \to \limits_{dup} abc , abc \mathop \to \limits_{cut} abc , ab,c \mathop \to \limits_{join} \Delta
\end{align*}
\end{document}
Example 4.
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$$\Gamma = acb$$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Delta = abab,cc$$
\end{document}
;
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$d{d_{SCJ}} ( \Gamma , \Delta ) = 8$$
\end{document}
;
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${d_{SCJD}} ( \Gamma , \Delta ) \le 7$$
\end{document}
:
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\begin{align*}
\Gamma \mathop \to \limits_{cut} a , cb \mathop \to \limits_{cut} a , b,c \mathop \to \limits_{join} ab,c \mathop \to \limits_{dup} ab,ab,c \mathop \to \limits_{dup} ab,ab,c , c \mathop \to \limits_{join} abab,c , c \mathop \to \limits_{join} \Delta
\end{align*}
\end{document}
Let
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${ \# _c} \Pi$$
\end{document}
be the number of linear chromosomes in genome
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$$\Pi$$
\end{document}
. Let
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma$$
\end{document}
be an ordinary linear genome and let
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$$\Delta$$
\end{document}
be a duplicated linear genome on the same gene set. A trivial upper bound for the SCJD distance between
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma$$
\end{document}
and
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$$\Delta$$
\end{document}
is given by solving the double distance between
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$$\Delta$$
\end{document}
and
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma$$
\end{document}
. This corresponds to first duplicating each chromosome in
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma$$
\end{document}
and then computing the SCJ distance between
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$$\Delta$$
\end{document}
and
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$$\Gamma { \kern 1pt} { \kern 1pt} \mathop \oplus \nolimits_ { \kern 1pt} { \kern 1pt} \Gamma$$
\end{document}
. We get
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$${d_{SCJD}} ( \Gamma , \Delta ) \le d{d_{SCJ}} ( \Gamma , \Delta ) + { \# _c} \Gamma$$
\end{document}
. However, Example 3 shows that this bound is not tight. It is tempting to guess that
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$$d{d_{SCJ}} ( \Gamma , \Delta ) \le {d_{SCJD}} ( \Gamma , \Delta )$$
\end{document}
. Alas, Example 4 shows this conjecture is incorrect.
4. Computing the SCJD Distance
In this section, we will solve the SCJD distance problem. The key idea is to show that there is an optimal scenario in which all the duplication operations are performed in sequence, one after the other. Having shown that, the sorting scenario between
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma$$
\end{document}
and
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Delta$$
\end{document}
can be presented as follows:
1. Transform
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$$\Gamma$$
\end{document}
into another ordinary linear genome,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime$$
\end{document}
, using only SCJ operations.
2. Duplicate all the chromosomes of
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$$\Gamma^\prime$$
\end{document}
resulting in a duplicated genome,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime \mathop \oplus \nolimits_ { \kern 1pt} { \kern 1pt} \Gamma^\prime$$
\end{document}
.
3. Solve the SCJ double distance problem between
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime$$
\end{document}
and
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Delta$$
\end{document}
.
Let
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$${O^*} = {o_1}, \ldots , {o_d}$$
\end{document}
be an optimal SCJD sorting scenario. Let
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$${ \Gamma _0} \equiv \Gamma$$
\end{document}
and for every
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$$1 \le i \le d$$
\end{document}
, let
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$${ \Gamma _i} = {o_i} ( { \Gamma _{i - 1}} )$$
\end{document}
be the genome resulting from performing oi on
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$${ \Gamma _{i - 1}}$$
\end{document}
. By definition,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${ \Gamma _d} \equiv \Delta$$
\end{document}
. Let Di be the set of duplicated genes in
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${ \Gamma _i}$$
\end{document}
. We have
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${D_0} = \emptyset$$
\end{document}
and
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$${D_d} = { \cal G}$$
\end{document}
. Given a gene set
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${\mathcal{H}}$$
\end{document}
, denote its extremity set by
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${ \mathcal{E}}_ {\mathcal{H}} = \{ {a_t} \vert a \in {\mathcal{H}} \} \cup \{ {a_h} \vert a \in \mathcal{H} \} $$
\end{document}
.
Proposition 1. In an optimal sorting scenario
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$${O^*}$$
\end{document}
, if oi is a join operation acting on the two telomeres, x and y, then either both
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$x , y \in { \mathcal{E}}_{{D_i}}$$
\end{document}
or both
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$x , y \,\notin \,{ \mathcal{E}}_{{D_i}}$$
\end{document}
.
Proof. Since oi is not a duplication, we have
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$${D_{i - 1}} = {D_i}$$
\end{document}
. Suppose by contradiction that
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$$x \in { \mathcal{E}}_{{D_i}}$$
\end{document}
, but
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$y \,\notin \,{ \mathcal{E}}_{{D_i}}$$
\end{document}
. Let oj (
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$i < j$$
\end{document}
) be the first duplication such that
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$y \in { \mathcal{E}}_{{D_j}}$$
\end{document}
. The duplication operation must act on a chromosome in which all genes are not yet duplicated. Therefore, there is a cut operation
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${o_k} ( i < k < j )$$
\end{document}
that breaks the adjacency
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\{ x , y \} $$
\end{document}
created by oi.
Let
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$$O^\prime = {o^\prime _1}, \ldots , {o^\prime _{d - 2}} = {o_1}, \ldots , {o_{i - 1}},{o_{i + 1}}, \ldots , {o_{k - 1}},{o_{k + 1}}, \ldots , {o_d}$$
\end{document}
be an alternative sorting sequence that results from removing oi and ok from
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${O^*}$$
\end{document}
. Let
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$${ \Gamma^\prime _0} \equiv \Gamma$$
\end{document}
, and denote
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$${ \Gamma^\prime _l} = {o^\prime _l} ( { \Gamma^\prime _{l - 1}} )$$
\end{document}
. For every l with
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$$1 \le l \le i - 1$$
\end{document}
, by definition,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${o^\prime _l} = {o_l}$$
\end{document}
and therefore
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$${ \Gamma^\prime _l} = { \Gamma _l}$$
\end{document}
.
We first show that for every l with
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$$i \le l \le k - 2$$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${ \Gamma^\prime _l} = { \Gamma _{l + 1}} \backslash \{ \{ x , y \} \} $$
\end{document}
. Since oi creates the adjacency
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$$\{ x , y \} $$
\end{document}
, we have
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$${ \Gamma _i} = { \Gamma _{i - 1}} \cup \{ \{ x , y \} \} $$
\end{document}
. For every such l,
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$${o^\prime _l} = {o_{l + 1}}$$
\end{document}
and since none of these operations creates a new copy of y, we have
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$${ \Gamma^\prime _l} = { \Gamma _{l + 1}} \backslash \{ \{ x , y \} \} $$
\end{document}
.
Next, we show that for every l with
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$$k - 1 \le l \le d - 2$$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${ \Gamma^\prime _l} = { \Gamma _{l + 2}}$$
\end{document}
. From the previous result and the fact that
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$${ \Gamma _k} = { \Gamma _{k - 1}} \backslash \{ \{ x , y \} \} $$
\end{document}
, we have
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$${ \Gamma^\prime _{k - 2}} = { \Gamma _k}$$
\end{document}
. Now, for every such l,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${o^\prime _l} = {o_{l + 2}}$$
\end{document}
and therefore
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${ \Gamma^\prime _l} = { \Gamma _{l + 2}}$$
\end{document}
.
We have established that
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$$O^\prime$$
\end{document}
is an SCJD sorting sequence of length,
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$$d - 2$$
\end{document}
, contradicting the optimality of
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$${O^*}$$
\end{document}
. ■
Proposition 2. In an optimal sorting scenario
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$${O^*}$$
\end{document}
, if oi is a cut operation acting on the adjacency
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\{ x , y \} $$
\end{document}
, then either
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$x , y \in { \mathcal{E}}_{{D_i}}$$
\end{document}
or
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$x , y \,\,\notin \,{ \mathcal{E}}_{{D_i}}$$
\end{document}
.
Proof. Suppose by contradiction,
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$$x \in { \mathcal{E}}_{{D_i}}$$
\end{document}
, but
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$y \,\,\notin\,\, { \mathcal{E}}_{{D_i}}$$
\end{document}
. Let oj (
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$$j < i$$
\end{document}
) be the first duplication such that
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$$x \in { \mathcal{E}}_{{D_j}}$$
\end{document}
. Since x was duplicated as part of a chromosome that did not contain y, there is subsequently a join operation
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${o_k} \,\,( j < k < i )$$
\end{document}
that creates the adjacency
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\{ x , y \} $$
\end{document}
. Defining
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$$O^\prime = {o^\prime _1}, \ldots , {o^\prime _{d - 2}} = {o_1}, \ldots , {o_{k - 1}},{o_{k + 1}}, \ldots , {o_{i - 1}},{o_{i + 1}}, \ldots , {o_d}$$
\end{document}
, we can get a shorter SCJD sorting scenario in a similar manner as the proof of Proposition 1. ■
Corollary 1. In an optimal sequence of SCJD operations, at the time of a cut or a join operation on the two extremities, x and y, either the genes corresponding to both x and y have already been duplicated or none of them have. ■
We say that a join operation in a sorting scenario is valid only if the two extremities it joins are not already part of any other adjacency. Similarly, a cut operation is valid only if the adjacency it breaks exists. A duplication operation is valid only if it duplicates a linear chromosome such that all its genes were not previously duplicated. A sorting scenario is valid if all its operations are valid.
Let
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$$S = {s_1}, \ldots , {s_m}$$
\end{document}
be a valid SCJD sorting scenario between
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma$$
\end{document}
and
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Delta$$
\end{document}
. We say the operation,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${s_{i + 1}}$$
\end{document}
, can preempt the operation, si, if the sequence,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$S^\prime = {s_1}, \ldots , {s_{i + 1}},{s_i}, \ldots , {s_m}$$
\end{document}
, is also a valid SCJD sorting scenario between
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma$$
\end{document}
and
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Delta$$
\end{document}
.
Proposition 3. In a valid SCJD scenario, S transforming
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma$$
\end{document}
into
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Delta$$
\end{document}
, if
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${s_{i + 1}}$$
\end{document}
is an SCJ operation acting on two extremities
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$x , y$$
\end{document}
that were not duplicated and si is a duplication, then
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${s_{i + 1}}$$
\end{document}
can preempt si.
Proof. Suppose si duplicates the linear chromosome C and produces another copy of it
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$C^\prime$$
\end{document}
. Since
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${s_{i + 1}}$$
\end{document}
operates on genes that are not duplicated yet, none of those genes belong to C or
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$C^\prime$$
\end{document}
. Therefore, the sequence,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${s_1}, \ldots , {s_{i - 1}},{s_{i + 1}}$$
\end{document}
, is valid. Any operation that creates an adjacency or a telomere of C must precede si. Hence,
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$${s_1}, \ldots , {s_{i - 1}},{s_{i + 1}},{s_i}$$
\end{document}
is valid. Finally, any sj for
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$j > i + 1$$
\end{document}
that requires the results of si or
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${s_{i + 1}}$$
\end{document}
is still valid. Thus,
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$$S^\prime = {s_1}, \ldots , {s_{i - 1}},{s_{i + 1}},{s_i},{s_{i + 2}}, \ldots , {s_m}$$
\end{document}
is a valid sequence.
To conclude the proof, we need to show that
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$${ \Gamma _{i + 1}} \equiv { \Gamma^\prime _{i + 1}}$$
\end{document}
. Indeed,
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$${s_{i + 1}}$$
\end{document}
does not alter any of the adjacencies or telomeres of C or
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$C^\prime$$
\end{document}
, and therefore,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${ \Gamma _{i + 1}} = {s_{i + 1}} ( { \Gamma _{i - 1}} \cup C^\prime ) \equiv {s_{i + 1}} ( { \Gamma _{i - 1}} ) \cup C^\prime = { \Gamma^\prime _{i + 1}}$$
\end{document}
. ■
Proposition 4. In a valid SCJD scenario, S transforming
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma$$
\end{document}
into
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Delta$$
\end{document}
, if
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$${s_{i + 1}}$$
\end{document}
is a duplication and si is a cut or join acting on two duplicated extremities, then
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${s_{i + 1}}$$
\end{document}
can preempt si.
Proof. Suppose si is an SCJ operation acting on the two extremities, x and y, such that the genes corresponding have both already been duplicated. Let
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$${s_{i + 1}}$$
\end{document}
be a duplication operation that takes the linear chromosome, C, and produces another copy of it,
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$$C^\prime$$
\end{document}
.
Since S is a valid sorting sequence, duplication operations that act on the genes corresponding to x and y must precede si. In addition, none of these genes are in C. Thus, the sequence,
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$${s_1}, \ldots , {s_{i - 1}},{s_{i + 1}},{s_i}$$
\end{document}
, is still valid. Any subsequent operation has its required set of adjacencies and telomeres and thus the sequence
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$$S^\prime = {s_1}, \ldots , {s_{i - 1}},{s_{i + 1}},{s_i},{s_{i + 2}}, \ldots , {s_m}$$
\end{document}
is valid. In addition, for the same reasons,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${ \Gamma _{i + 1}} = {s_i} ( { \Gamma _{i - 1}} ) \cup C^\prime \equiv {s_i} ( { \Gamma _{i - 1}} \cup C^\prime ) = { \Gamma^\prime _{i + 1}}$$
\end{document}
. ■
Proposition 5. In a valid SCJD scenario, S transforming
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma$$
\end{document}
into
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Delta$$
\end{document}
, if
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${s_{i + 1}}$$
\end{document}
is an SCJ acting on two extremities that were not duplicated yet and si is an SCJ acting on two duplicated extremities, then
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${s_{i + 1}}$$
\end{document}
can preempt si.
Proof. If
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$$\alpha \in \Gamma$$
\end{document}
, then
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$$\alpha^\prime \,\,\notin \,\,\Gamma$$
\end{document}
since
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma$$
\end{document}
is an ordinary genome. In addition, since
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta ( \alpha ) > 0$$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\vert { \Delta _ \alpha } \vert > 0$$
\end{document}
, therefore
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$$\vert { \Delta _{ \alpha^\prime }} \vert < 2$$
\end{document}
. Thus,
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$$\eta ( \alpha^\prime ) \le 0$$
\end{document}
. If
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\alpha \,\,\notin \,\,\Gamma$$
\end{document}
, then to achieve
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$$\eta ( \alpha ) > 0$$
\end{document}
, we must have
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$$\vert { \Delta _ \alpha } \vert = 2$$
\end{document}
, so in particular
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$$\vert { \Delta _{ \alpha^\prime }} \vert = 0$$
\end{document}
and therefore
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta ( \alpha^\prime ) \le 0$$
\end{document}
. ■
For a sequence of SCJ operations, S, let SD (
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${ \overline S ^D}$$
\end{document}
, respectively) be the subsequence of operations that act on two extremities of genes that have (have not, respectively) already been duplicated at the time of the operation. By Corollary 1, for optimal S,
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$${ \overline S ^D}$$
\end{document}
is indeed the complement of SD.
Proposition 6. There exists an optimal sorting scenario in which all duplication events are consecutive.
Proof. Let
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$${o_{{i_1}}}, \ldots , {o_{{i_p}}}$$
\end{document}
be the duplication events in an optimal sorting scenario. Denote by
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$${S_{{i_j}}}$$
\end{document}
the sequence of SCJ operations occurring between the duplications,
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$${o_{{i_j}}}$$
\end{document}
and
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$${o_{{i_{j + 1}}}}$$
\end{document}
. In addition, denote by
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$${S_{{i_0}}}$$
\end{document}
and
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$${S_{{i_p}}}$$
\end{document}
the sequence of SCJ operations before the first duplication and after the last duplication, respectively.
Given an optimal scenario,
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$${O^*} = {S_{{i_0}}},{o_{{i_1}}},{S_{{i_1}}},{o_{{i_2}}},{S_{{i_2}}}, \ldots , {S_{{i_{p - 1}}}},{o_{{i_p}}},{S_{{i_p}}}$$
\end{document}
, we modify it into a new sorting scenario
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$$O^\prime$$
\end{document}
as follows: using Propositions 3 and 5, preempt SCJ operations acting on unduplicated genes. Using Proposition 4, preempt duplication events. These steps are iterated until no preemption is possible. We get that
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$$O^\prime = {S_{{i_0}}}, \overline S _{{i_1}}^D , \ldots , \overline S _{{i_p}}^D ,$$
\end{document}
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$${o_{{i_1}}}, \ldots , {o_{{i_p}}},S_{{i_1}}^D , \ldots , S_{{i_{p - 1}}}^D , {S_{{i_p}}}$$
\end{document}
is a valid SCJD optimal sequence in which all duplications are consecutive. ■
Corollary 2. There exists an optimal SCJD sorting scenario, consisting, in this order, of (1) SCJ operations on single-copy genes, (2) duplications, and (3) SCJ operations acting on duplicated genes. ■
Denote by
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$$\Gamma^\prime$$
\end{document}
the intermediate (ordinary) genome after step (1). Then, we can conclude the following:
Theorem 3.
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$${d_{SCJD}} ( \Gamma , \Delta ) = \mathop { \min } \nolimits_{ \Gamma^\prime } \left( {{d_{SCJ}} ( \Gamma , \Gamma^\prime ) + { \# _c} \Gamma^\prime + d{d_{SCJ}} ( \Gamma^\prime , \Delta ) } \right) \quad$$
\end{document}
■
Recall that n is the number of genes in
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$$\Gamma$$
\end{document}
. Using Theorems 1 and 2 and the fact that
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$${ \# _c} \Pi = n - \vert \Pi \vert$$
\end{document}
, the distance formula can be simplified as follows:
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\begin{align*}
\begin{split} & {d_{SCJD}} = \mathop { \min } \limits_{
\Gamma^\prime } \left( { \vert \Gamma \vert + \vert \Gamma^\prime
\vert - 2 \vert \Gamma \cap \Gamma^\prime \vert + n - \vert
\Gamma^\prime \vert + \vert \Delta \vert + 2 \mathop \sum
\limits_{ \alpha \in A} \vert {{ \Gamma^\prime }_ \alpha } \vert (
1 - \vert { \Delta _ \alpha } \vert ) } \right) \\ & = n + \vert
\Delta \vert + \vert \Gamma \vert - 2 \mathop { \max } \limits_{
\Gamma^\prime } \left( { \vert \Gamma \cap \Gamma^\prime \vert +
\mathop \sum \limits_{ \alpha \in A} \vert {{ \Gamma^\prime }_
\alpha } \vert ( \vert { \Delta _ \alpha } \vert - 1 ) } \right)
\\ & = n + \vert \Delta \vert + \vert \Gamma \vert - 2 \mathop {
\max } \limits_{ \Gamma^\prime } \mathop \sum \limits_{ \alpha \in
\Gamma^\prime } ( \vert { \Gamma _ \alpha } \vert + \vert { \Delta
_ \alpha } \vert - 1 ) \\ & = n + \vert \Delta \vert + \vert
\Gamma \vert - 2 \mathop { \max } \limits_{ \Gamma^\prime }
\mathop \sum \limits_{ \alpha \in \Gamma^\prime } \eta ( \alpha )
= n + \vert \Delta \vert + \vert \Gamma \vert - 2 \mathop { \max }
\limits_{ \Gamma^\prime } H ( \Gamma^\prime ) \end{split}
\tag{2}
\end{align*}
\end{document}
where
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$$\eta ( \alpha ) = \eta ( \alpha , \Gamma , \Delta ) = \vert { \Gamma _ \alpha } \vert + \vert { \Delta _ \alpha } \vert - 1$$
\end{document}
and
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$$H ( \Gamma^\prime ) = \sum \nolimits_{ \alpha \in \Gamma^\prime } \eta ( \alpha )$$
\end{document}
. Intuitively,
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$$H ( \Gamma^\prime )$$
\end{document}
measures the similarity of
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime$$
\end{document}
to
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma$$
\end{document}
and
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Delta$$
\end{document}
in terms of adjacencies. Since we want to maximize
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$$H ( \Gamma^\prime )$$
\end{document}
, we will focus on adjacencies with positive contribution in Equation (2).
Lemma 2. Let
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$$\alpha = \{ x , y \} $$
\end{document}
be an adjacency such that
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$$\eta ( \alpha ) > 0$$
\end{document}
. Then, for every extremity
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$z \ne y$$
\end{document}
, the conflicting adjacency
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\alpha^\prime = \{ x , z \} $$
\end{document}
has
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta ( \alpha^\prime ) \le 0$$
\end{document}
.
Proof. If
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\alpha \in \Gamma$$
\end{document}
, then
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\alpha^\prime \,\,\notin \,\,\Gamma$$
\end{document}
since
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma$$
\end{document}
is an ordinary genome. In addition, since
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta ( \alpha ) > 0$$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\vert { \Delta _ \alpha } \vert > 0$$
\end{document}
, therefore
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\vert { \Delta _{ \alpha^\prime }} \vert < 2$$
\end{document}
. Thus,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta ( \alpha^\prime ) \le 0$$
\end{document}
. If
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\alpha \,\,\notin \,\,\Gamma$$
\end{document}
, then to achieve
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta ( \alpha ) > 0$$
\end{document}
, we must have
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\vert { \Delta _ \alpha } \vert = 2$$
\end{document}
, so in particular
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\vert { \Delta _{ \alpha^\prime }} \vert = 0$$
\end{document}
and therefore
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta ( \alpha^\prime ) \le 0$$
\end{document}
. ■
Combining Lemma 2 and Theorem 3, we get a closed formula for the SCJD distance:
Theorem 4. The genome
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime = \{ \alpha = \{ x , y \} \vert \eta ( \alpha ) > 0 \} $$
\end{document}
minimizes Equation (2). If
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime$$
\end{document}
is a linear genome, then the SCJD distance is given by
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${d_{SCJD}} ( \Gamma , \Delta ) = n + \vert \Delta \vert + \vert \Gamma \vert - 2H ( \Gamma^\prime )$$
\end{document}
. ■
Let us return to the examples in Section 3:
− Example 1:
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$$n = 1$$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\vert \Delta \vert = 1$$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\vert \Gamma \vert = 0$$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime = \emptyset$$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$H ( \Gamma^\prime ) = 0 \to d = 1 + 1 + 0 - 2*0 = 2$$
\end{document}
− Example 2:
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$n = 2$$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\vert \Delta \vert = 2$$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\vert \Gamma \vert = 1$$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime = \{ \{ {a_h},{b_t} \} \} $$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$H ( \Gamma^\prime ) = 2 \to d = 2 + 2 + 1 - 2*2 = 1$$
\end{document}
− Example 3:
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$n = 3$$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\vert \Delta \vert = 4$$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\vert \Gamma \vert = 1$$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime = \{ \{ {a_h},{b_t} \} , \{ {b_h},{c_t} \} \} $$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$H ( \Gamma^\prime ) = 1 + 1 \to d = 3 + 4 + 1 - 2*2 = 4$$
\end{document}
− Example 4:
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$$n = 3$$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\vert \Delta \vert = 4$$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\vert \Gamma \vert = 2$$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime = \{ \{ {a_h},{b_t} \} \} $$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$H ( \Gamma^\prime ) = 1 \to d = 3 + 4 + 2 - 2*1 = 7$$
\end{document}
Example 5.
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$$\Gamma = abc$$
\end{document}
and
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Delta = cab,bca$$
\end{document}
. According to Theorem 4, we get
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime = ( abc )$$
\end{document}
because
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta ( \{ {a_h},{b_t} \} ) = \eta ( \{ {b_h},{c_t} \} ) = \eta ( \{ {c_h},{a_t} \} ) = 1$$
\end{document}
. The corresponding distance is
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$d = 3 ,$$
\end{document}
providing the following invalid sorting scenario:
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
\begin{align*}
\Gamma \mathop \to \limits_{join} ( abc ) \mathop \to \limits_{du{p^*}} ( abc ) , ( abc ) \mathop \to \limits_{cut} cab, ( abc ) \mathop \to \limits_{cut} \Delta
\end{align*}
\end{document}
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$du{p^*}$$
\end{document}
indicates a duplication of a circular chromosome, an operation that is not allowed in the SCJD model (and has no cost). It is not difficult to verify that there is no valid sorting scenario with
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$d \le3$$
\end{document}
.
The reason for the discrepancy in Example 5 is that
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${ \# _c} ( \Gamma^\prime ) = n - \vert \Gamma^\prime \vert = 0$$
\end{document}
is not equal to the number of duplications if there are circular chromosomes. Therefore, to minimize the SCJD distance given by Equation (2), we need to maximize
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$H ( \Gamma^\prime )$$
\end{document}
under the constraint that
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime$$
\end{document}
is a linear genome, that is,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$H ( \Gamma^\prime ) \ge H ( \tilde \Gamma )$$
\end{document}
for every linear genome
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\tilde \Gamma$$
\end{document}
. Lemma 3 shows that we can do so simply by removing one adjacency with
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta = 1$$
\end{document}
from each circular chromosome in
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime$$
\end{document}
and that such adjacency must exist.
Lemma 3. Let
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime = \{ \alpha = \{ x , y \} \vert \eta ( \alpha ) > 0 \} $$
\end{document}
and let
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${{\Gamma}^{\prime}}^{\prime}$$
\end{document}
be a genome obtained by removing one adjacency
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\alpha$$
\end{document}
with
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta ( \alpha ) = 1$$
\end{document}
from each circular chromosome in
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime$$
\end{document}
. Then,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${{\Gamma}^{\prime}}^{\prime}$$
\end{document}
is a linear genome that maximizes
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$H ( \cdot )$$
\end{document}
and the SCJD distance is given by
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$${d_{SCJD}} ( \Delta , \Gamma ) = n + \vert \Delta \vert + \vert
\Gamma \vert - 2H ({{\Gamma}^{\prime}}^{\prime})$$
\end{document}
.
Proof. Let
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Pi$$
\end{document}
be an ordinary linear genome maximizing
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$H ( \Pi )$$
\end{document}
. From the maximality of
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$H ( \Pi )$$
\end{document}
, we may assume w.l.o.g. that
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Pi$$
\end{document}
does not contain adjacencies with
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta ( \alpha ) \le 0$$
\end{document}
. By the definition of
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime$$
\end{document}
and from Lemma 2, we have that
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\forall \alpha \in \Pi$$
\end{document}
if
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta ( \alpha ) > 0$$
\end{document}
, then
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\alpha \in \Gamma^\prime$$
\end{document}
. It follows that
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Pi \subseteq \Gamma^\prime$$
\end{document}
. Therefore, every linear chromosome in
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime$$
\end{document}
is also in
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Pi$$
\end{document}
.
Since
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Pi \subseteq \Gamma^\prime$$
\end{document}
, any linear chromosome C in
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Pi$$
\end{document}
that is not in
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime$$
\end{document}
must be fully contained in a circular chromosome
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$C^\prime$$
\end{document}
of
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime$$
\end{document}
. From the maximality of
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Pi$$
\end{document}
, C must contain all adjacencies in
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$C^\prime$$
\end{document}
except for one adjacency
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\alpha$$
\end{document}
with minimum
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta ( \alpha )$$
\end{document}
.
Since
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime$$
\end{document}
contains only adjacencies with
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta ( \alpha ) = 1$$
\end{document}
or 2, the minimal value is an adjacency with
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta ( \alpha ) = 1$$
\end{document}
if one exists. If
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$C^\prime$$
\end{document}
contains only adjacencies with
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta ( \alpha ) = 2$$
\end{document}
, it follows that
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\vert { \Gamma _ \alpha } \vert = 1$$
\end{document}
for every
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\alpha \in C^\prime$$
\end{document}
, so
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma$$
\end{document}
contains the circular chromosome
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$C^\prime$$
\end{document}
, contradicting the linearity of
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma$$
\end{document}
. Hence,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$C^\prime$$
\end{document}
must contain at least one adjacency with
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta ( \alpha ) = 1$$
\end{document}
. ■
Applying Lemma 3 to Example 5, we get
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma ^{\prime \prime} = abc$$
\end{document}
and
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$d = 5$$
\end{document}
:
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
\begin{align*}
\Gamma \mathop \to \limits_{dup} abc , abc \mathop \to \limits_{cut} a , bc , abc \mathop \to \limits_{join} bca , abc \mathop \to \limits_{cut} bca , ab,c \mathop \to \limits_{join} \Delta
\end{align*}
\end{document}
Instead, we can choose
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma \prime \prime = cab$$
\end{document}
, which gives a different optimal sorting scenario:
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
\begin{align*}
\Gamma \mathop \to \limits_{cut} ab,c \mathop \to \limits_{join} cab \mathop \to \limits_{dup} cab,cab \mathop \to \limits_{cut} cab,a , bc \mathop \to \limits_{join} \Delta
\end{align*}
\end{document}
Algorithm 1 gives the full procedure for solving the SCJD distance and sorting problems. Each step of the algorithm takes
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$O ( \vert \Gamma \vert + \vert \Delta \vert )$$
\end{document}
time. In conclusion:
Theorem 5. Algorithm 1 computes the SCJD distance in linear time. ■
5. Controlling the Number of Duplications
In this section, we discuss how to control the number of duplications in an optimal SCJD sequence. Since the number of duplications is
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$n - \vert \Gamma ^{\prime\prime} \vert$$
\end{document}
, selecting different intermediate genomes
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma ^{\prime\prime}$$
\end{document}
that preserve the SCJD distance can produce scenarios with different number of duplications.
An optimal SCJD scenario with fewer duplications can be viewed as more conservative. The assumption behind this is that duplications are more radical events than breakage (cut) or fusion (join), which are local events.
Lemma 4. Algorithm 1 gives an optimal sorting scenario with a maximum number of duplications.
Proof. Observe first that for any sorting scenario (optimal or suboptimal) transforming
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma$$
\end{document}
into
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Delta$$
\end{document}
, we can assume w.l.o.g. that all duplications are consecutive without affecting the number of operations (Corollary 2). Call the genome right before the duplications the last ordinary genome. Denote by
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$d ( \Gamma , \Pi , \Delta )$$
\end{document}
the shortest scenario transforming
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma$$
\end{document}
into
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Delta$$
\end{document}
given that the last ordinary genome is
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Pi$$
\end{document}
. The proof of Theorem 3 implies that
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$d ( \Gamma , \Pi , \Delta ) = n + \vert \Delta \vert + \vert \Gamma \vert - 2H ( \Pi )$$
\end{document}
.
Let
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime$$
\end{document}
be the last ordinary genome produced by the algorithm. Consider an optimal scenario O with a maximum number of duplications and let
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\tilde \Gamma$$
\end{document}
be the last ordinary linear genome in O. Since O is optimal,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$H ( \tilde \Gamma )$$
\end{document}
must be maximal. Hence,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\tilde \Gamma$$
\end{document}
cannot contain adjacencies with
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta < 0$$
\end{document}
. Moreover, it cannot contain adjacencies with
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta = 0$$
\end{document}
as such adjacencies increase
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\vert \tilde \Gamma \vert$$
\end{document}
and thus decrease the number of duplications in O. Therefore,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\tilde \Gamma \subseteq \Gamma^\prime$$
\end{document}
.
We now show that
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\forall \alpha \in \Gamma^\prime \backslash \tilde \Gamma$$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta ( \alpha ) = 1$$
\end{document}
. Suppose by contradiction that there is an adjacency
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\alpha \in \Gamma^\prime \backslash \tilde \Gamma$$
\end{document}
with
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta ( \alpha ) > 1$$
\end{document}
and let
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Pi = \tilde \Gamma \cup \{ \alpha \} $$
\end{document}
. If
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Pi$$
\end{document}
is a linear genome,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$d ( \Gamma , \Pi , \Delta ) < d ( \Gamma , \tilde \Gamma , \Delta )$$
\end{document}
, contradicting the optimality of O. Otherwise,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Pi$$
\end{document}
contains a circular chromosome and by Lemma 3, there is an adjacency
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\beta \in \tilde \Gamma$$
\end{document}
with
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta ( \beta ) = 1$$
\end{document}
such that
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Pi \backslash \{ \beta \} $$
\end{document}
is a linear genome with
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$H ( \Pi \backslash \{ \beta \} ) > H ( \tilde \Gamma )$$
\end{document}
, again contradicting the optimality of O. Thus,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\vert \Gamma^\prime \backslash \tilde \Gamma \vert = \vert \Gamma^\prime \vert - \vert \tilde \Gamma \vert = H ( \Gamma^\prime ) - H ( \tilde \Gamma )$$
\end{document}
.
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime$$
\end{document}
may contain circular chromosomes. By Lemma 3,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma ^{\prime\prime}$$
\end{document}
is produced by removing one adjacency with
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta = 1$$
\end{document}
from each circular chromosome in
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma^\prime$$
\end{document}
. Hence,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\vert \Gamma^\prime \backslash \Gamma^{\prime\prime} \vert = \vert \Gamma^\prime \vert - \vert \Gamma ^{\prime\prime} \vert = H ( \Gamma \prime ) - H ( \Gamma ^{\prime\prime} )$$
\end{document}
.
Since both
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\tilde \Gamma$$
\end{document}
and
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma ^{\prime\prime}$$
\end{document}
are last ordinary genomes, in optimal SCJD scenarios,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$H ( \tilde \Gamma ) = H ( \Gamma ^{\prime\prime} )$$
\end{document}
. Thus,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$ {\vert} {{\Gamma}^{\prime}} \vert - \vert \tilde \Gamma \vert =
H {(\Gamma^{\prime} )} - H (\tilde \Gamma) = H {(\Gamma^{\prime})}
- H ({{\Gamma}^{\prime}}^{\prime}) = \vert {{\Gamma}^{\prime}}
\vert - \vert {{\Gamma}^{\prime}}^{\prime} \vert$$
\end{document}
, which implies that
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\vert \tilde \Gamma \vert = \vert \Gamma ^{\prime\prime} \vert$$
\end{document}
. ■
One can decrease the number of duplications in an optimal SCJD scenario by adding adjacencies with
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\eta ( \alpha ) = 0$$
\end{document}
to
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma ^{\prime\prime}$$
\end{document}
. However, we need to make sure that the resulting genome is still linear. Consider the following example:
Example 6:
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Gamma = a , b,c$$
\end{document}
,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Delta = abccba$$
\end{document}
. From Theorem 4, we have that
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$$\Gamma^\prime = \Gamma$$
\end{document}
and so the SCJD distance is 8. The scenario produced by Algorithm 1 will first duplicate the three chromosomes of
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$$\Gamma$$
\end{document}
and then perform five joins to create
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$$\Delta$$
\end{document}
. An alternative optimal sorting scenario is as follows:
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\begin{align*}
\Gamma \mathop \to \limits_{JJ} abc \mathop \to \limits_D abc , abc \mathop \to \limits_{CC} abc , a , b,c \mathop \to \limits_{JJJ} \Delta
\end{align*}
\end{document}
Here, since each adjacency
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$$\alpha \in \Delta$$
\end{document}
has
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$$\eta ( \alpha ) = 0$$
\end{document}
, we chose
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$$\Gamma ^{\prime\prime} = abc$$
\end{document}
and obtained an optimal scenario with a single duplication. In contrast, if we add to
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$$\Gamma ^{\prime\prime}$$
\end{document}
the adjacencies
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$$\{ {b_h},{c_t} \} $$
\end{document}
and
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$$\{ {c_h},{b_t} \} $$
\end{document}
(which also have
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$$\eta = 0$$
\end{document}
), we create a circular chromosome and an invalid SCJD sorting scenario.
To minimize the number of duplications, we must add to
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$$\Gamma ^{\prime\prime}$$
\end{document}
a maximum set of adjacencies with
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$$\eta = 0$$
\end{document}
such that the resulting genome is still linear. Here, we show that this problem is NP-hard using a reduction similar to (Kováč, 2014).
Theorem 6. Given an ordinary linear genome,
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$$\Gamma$$
\end{document}
, a duplicated linear genome,
\documentclass{aastex}\usepackage{amsbsy}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{bm}\usepackage{mathrsfs}\usepackage{pifont}\usepackage{stmaryrd}\usepackage{textcomp}\usepackage{portland, xspace}\usepackage{amsmath, amsxtra}\pagestyle{empty}\DeclareMathSizes{10}{9}{7}{6}\begin{document}
$$\Delta$$
\end{document}
, on the same gene set, and an integer, k, the problem of finding an optimal SCJD scenario with at most k duplications is NP-hard.
Proof. Call a directed graph in which all in- and out-degrees are 2 a 2-digraph. Deciding if a 2-digraph contains a Hamiltonian cycle is NP-hard (Plesnik, 1979; Kováč, 2014). This implies that the following variant is also NP-hard: given a 2-digraph, G, with an edge,
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$$( x , y )$$
\end{document}
, decide if there is a Hamiltonian path from y to x in G.
Let
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$$G = ( V , E )$$
\end{document}
be a 2-digraph with an edge
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$$( x , y )$$
\end{document}
as above. We may assume w.l.o.g. that G is strongly connected since otherwise it would not contain a Hamiltonian path from y to x. Notice that
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$$G \backslash ( x , y )$$
\end{document}
contains an Eulerian path from y to x (Cormen et al., 2001). Denote it by
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$$P = {e_1},{e_2}, \ldots , {e_m}$$
\end{document}
.
We construct a duplicated genome
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$$\Sigma$$
\end{document}
as follows: for each
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$${e_q} = ( u , v ) \in P$$
\end{document}
, add the adjacency,
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$$\{ u_h^i , v_t^j \} $$
\end{document}
, where
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$$i = 2$$
\end{document}
if there is an edge
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$${e_l} = ( u , v^\prime )$$
\end{document}
with
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$$l < q$$
\end{document}
and
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$$i = 1$$
\end{document}
otherwise. Similarly,
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$$j = 2$$
\end{document}
if there is an edge
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$${e_m} = ( u^\prime ,v )$$
\end{document}
with
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$$m < q$$
\end{document}
and
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$$j = 1$$
\end{document}
otherwise. The result is a linear chromosome created by traversing P and numbering the first occurrence of each vertex v in P as the gene copy v1 and the second occurrence as v2. Denote by
the sequence of genes along the path P. In addition, we add two new genes
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$$w , z$$
\end{document}
and the adjacencies
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$$\{ w_h^1 , y_t^1 \} , \{ x_h^2 , z_t^1 \} $$
\end{document}
. Thus,
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$$\Sigma$$
\end{document}
has three linear chromosomes:
and z2. Let
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$$\Pi = \{ \{ {w_h},{y_t} \} , \{ {x_h},{z_t} \} \} $$
\end{document}
be an ordinary genome with n chromosomes over the same set of genes. (Note that every vertex in
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$$V \backslash \{ x , y \} $$
\end{document}
corresponds to a separate chromosome in
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$$\Pi$$
\end{document}
).
Let
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$${ \Sigma _{ ( i ) }}$$
\end{document}
and
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$${ \Pi _{ ( i ) }}$$
\end{document}
be genomes in which every gene
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$$v \in V$$
\end{document}
is renamed
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$${v_{ ( i ) }}$$
\end{document}
. We define
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$$\Delta = \bigcup \nolimits_{i = 1}^k { \Sigma _{ ( i ) }}$$
\end{document}
and
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$$\Gamma = \bigcup \nolimits_{i = 1}^k { \Pi _{ ( i ) }}$$
\end{document}
to be the disjoint union of k different copies of
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$$\Sigma$$
\end{document}
and
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$$\Pi$$
\end{document}
, respectively. This completes the reduction, which is clearly polynomial. We will show that there is an optimal SCJD scenario between
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$$\Gamma$$
\end{document}
and
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$$\Delta$$
\end{document}
with at most k duplications if G admits a Hamiltonian path from y to x.
For each edge
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$$e = ( u , v ) \in E$$
\end{document}
and every
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$$i ,$$
\end{document}
the corresponding adjacency
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$$\alpha = \{ ( {u_{ ( i ) }} ) _h^j , ( {v_{ ( i ) }} ) _t^l \} $$
\end{document}
has
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$$\eta ( \alpha ) = 1$$
\end{document}
if there are two parallel edges from u to v and
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$$\eta ( \alpha ) = 0$$
\end{document}
otherwise. In addition, for every i,
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$$\eta ( \{ ( {w_{ ( i ) }}{ ) _h}, ( {y_{ ( i ) }}{ ) _t} \} ) = \eta ( \{ ( {x_{ ( i ) }}{ ) _h}, ( {z_{ ( i ) }}{ ) _t} \} ) = 1$$
\end{document}
, and every other adjacency of
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$${w_{ ( i ) }},{z_{ ( i ) }}$$
\end{document}
has
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$$\eta < 0$$
\end{document}
.
Suppose G contains a Hamiltonian path S from y to x. Let
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$$\Gamma^\prime$$
\end{document}
be the genome formed by the set of adjacencies
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$$\{ \{ ( {w_{ ( i ) }}{ ) _h}, ( {y_{ ( i ) }}{ ) _t} \} , \{ ( {x_{ ( i ) }}{ ) _h}, ( {z_{ ( i ) }}{ ) _t} \} \vert i = 1 \ldots k \} \cup \ \{ \{ ( {u_{ ( i ) }}{ ) _h}, ( {v_{ ( i ) }}{ ) _t} \} \vert ( u , v ) \in S,i = 1 \ldots k \} $$
\end{document}
. Since S is a Hamiltonian path,
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$$\Gamma^\prime$$
\end{document}
is a valid ordinary linear genome with k chromosomes of the form
. To prove that
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$$\Gamma^\prime$$
\end{document}
maximizes
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$$H ( \cdot )$$
\end{document}
, we need to show it contains every adjacency with
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$$\eta = 1$$
\end{document}
and no adjacency with
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$$\eta < 0$$
\end{document}
. Indeed (suppressing the copy index i for clarity), the only adjacencies
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$$\alpha$$
\end{document}
with
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$$\eta ( \alpha ) = 1$$
\end{document}
are
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$$\{ {w_h},{y_t} \} , \{ {x_h},{z_t} \} $$
\end{document}
(
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$$\vert { \Delta _ \alpha } \vert = \vert { \Gamma _ \alpha } \vert = 1$$
\end{document}
) and parallel edges in G (
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$$\vert { \Delta _ \alpha } \vert = 2 , \vert { \Gamma _ \alpha } \vert = 0$$
\end{document}
), one copy of which must be included in S. All other adjacencies in
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$$\Gamma^\prime$$
\end{document}
have
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$$\vert { \Delta _ \alpha } \vert = 1 , \vert { \Gamma _ \alpha } \vert = 0$$
\end{document}
and
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$$\eta ( \alpha ) = 0$$
\end{document}
. We conclude that
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$$\Gamma^\prime$$
\end{document}
is part of an optimal scenario with k duplications.
Conversely, suppose there is an optimal scenario
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$${O^*}$$
\end{document}
with at most k duplications and let
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$$\tilde \Gamma$$
\end{document}
be the last ordinary genome in
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$${O^*}$$
\end{document}
. Let
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$$\Gamma^\prime = \{ \alpha \vert \eta ( \alpha ) > 0 \} $$
\end{document}
be a genome that minimizes the SCJD distance according to Theorem 4. First, notice that
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$$\Gamma^\prime$$
\end{document}
is indeed a linear genome. Otherwise, a circular chromosome of adjacencies with
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$$\eta ( \alpha ) = 1$$
\end{document}
would imply a strongly connected component without the vertices
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$$x , y$$
\end{document}
, contradicting the strong connectivity of G. It follows that
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$$\Gamma^\prime \subseteq \tilde \Gamma$$
\end{document}
,
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$$H ( \Gamma^\prime ) = H ( \tilde \Gamma )$$
\end{document}
, and
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$${ \# _c} \tilde \Gamma \le k$$
\end{document}
.
Since
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$${ \Sigma _{ ( i ) }}$$
\end{document}
and
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$${ \Sigma _{ ( j ) }}$$
\end{document}
for
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$$i \ne j$$
\end{document}
contain different genes, an adjacency between a gene in
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$${ \Sigma _{ ( i ) }}$$
\end{document}
and a gene
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$${ \Sigma _{ ( j ) }}$$
\end{document}
has negative
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$$\eta$$
\end{document}
. Therefore,
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$$\tilde \Gamma$$
\end{document}
contains no such adjacencies. Since
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$$\tilde \Gamma$$
\end{document}
has at most k linear chromosomes, it must contain exactly k linear chromosomes, each containing all the genes of
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$${ \Sigma _{ ( i ) }}$$
\end{document}
for one i.
Let
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$$C = {w_{ ( 1 ) }}{y_{ ( 1 ) }} \ldots {x_{ ( 1 ) }}{z_{ ( 1 ) }}$$
\end{document}
be the linear chromosome in
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$$\tilde \Gamma$$
\end{document}
that contains all the genes of
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$${ \Sigma _{ ( 1 ) }}$$
\end{document}
. Define an edge set S in G by taking for each adjacency
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$$\{ ( {u_{ ( 1 ) }}{ ) _h}, ( {v_{ ( 1 ) }}{ ) _t} \} \in C \backslash \{ \{ ( {w_{ ( 1 ) }}{ ) _h}, ( {y_{ ( 1 ) }}{ ) _t} \} , \{ ( {x_{ ( 1 ) }}{ ) _h}, ( {z_{ ( 1 ) }}{ ) _t} \} \} $$
\end{document}
the edge
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$$( u , v )$$
\end{document}
. Since C is an ordinary linear chromosome containing all the genes of
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$${ \Sigma _{ ( 1 ) }}$$
\end{document}
, S is a Hamiltonian path in G from y to x. ■