3.1. convex set
3.1.1. Geodetic
Let G[S] be the subgraph induced by
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$$S \subseteq V ( G )$$
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. If G[S] is isomorphic to
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$${Q_{n \prime }}$$
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, where
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$$n \prime = { \log _2} \vert S \vert < n$$
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, then between any two vertices of S the vertices of all shortest paths linking them are in S, since a vertex v outside
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$${Q_{n \prime }}$$
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is associated with a string sv such that sv[j] (the bit at position j in sv) satisfies
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$${s_v} [ j ] \ne {s_u} [ j ]$$
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for every
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$$u \in S$$
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, that is, there is no shortest path between two vertices of S through v. (Note that, since G[S] is an
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$$n \prime$$
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-dimensional cube, there is at least one position j such that su[j] has the same bit value for all u ∈ S.) Conversely, suppose that G[S] is not isomorphic to
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$${Q_{n \prime }}$$
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for any value of
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$$n \prime$$
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. Let k be the minimum integer for which S is entirely contained in a subgraph H of G isomorphic to the k-dimensional cube Qk. In this case, there exists at least one vertex v of H such that
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$$v \notin S$$
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and there is a shortest path between two vertices of S through v. Hence S is not convex, since v ∈ I(S).
Theorem 1 Let
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$$S \subseteq V ( G )$$
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. In the geodetic convexity, S is convex if and only if G[S] is isomorphic to
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$${Q_{n \prime }}$$
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where
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$$n \prime = { \log _2} \vert S \vert$$
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.
We can decide in polynomial time if S is isomorphic to
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$${Q_{n \prime }}$$
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, since we must have (a)
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$$\vert S \vert = {2^{n \prime }}$$
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; (b)
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$$n - \vert S \vert$$
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positions have with the same bit value in all strings su for u ∈ S.
3.1.2. Monophonic
It is clear that S is convex for the cases |S| = 1, |S| = 2 (with two adjacent elements), and S = V (G). Conversely, suppose
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$$2 < \vert S \vert < \vert V ( G ) \vert$$
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. Then there exist three vertices u, v, w in S such that u is not adjacent to v, because G is bipartite and contains no triangles. Since
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$$\vert S \vert < \vert V ( G ) \vert$$
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, there is an induced path between u and v through a vertex x ≠ w, because G is biconnected. This implies that S is not convex.
Theorem 2
Let
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$$S \subseteq V ( G )$$
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. In the monophonic convexity, S is convex if and only if |S| = 1, or |S| = 2 with two adjacent elements, or S = V (G).
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$${{ \textbf{\textit{P}}}_{ \textbf{\textit{3}}}}$$
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and
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$${ \textbf{\textit{P}}}_{ \textbf{\textit{3}}}^*$$
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convexities. Since every hypercube is bipartite, G contains no triangles, and thus the P3 and
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$$P_3^*$$
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convexities are identical in this case. Let
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$$S \subseteq V ( G )$$
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. Then S is convex if and only if every two vertices in S at distance two have their common neighbor also in S. Since we can easily check if a string is at distance one from two other distinct strings by analyzing mismatched zeros and ones, we have the following:
Theorem 3 Let
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$$S \subseteq V ( G )$$
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. In the P3 and
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$$P_3^*$$
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convexities, we can check if S is convex in time polynomial in n and
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$$\vert S \vert$$
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.
3.2. interval determination
3.2.1. Geodetic
Let
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$$S \subseteq V ( G )$$
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and
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$$z \in V ( G )$$
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. Then z belongs to I(S) if and only if
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$$d ( {s_i} , z ) + d ( z , {s_j} ) = d ( {s_i} , {s_j} )$$
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, for some
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$${s_i} , {s_j} \in S$$
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. We can easily determine such distances by a pairwise check of agreeing positions (those with identical bit values). Hence the following:
Theorem 4 geodetic-id is solvable in time polynomial in n and
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$$\vert S \vert$$
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.
Note that
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$$I ( S ) = {Q_{n \prime }}$$
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for some
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$$n \prime \le n$$
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, that is, I(S) is convex. Thus, I(S) = H(S).
3.2.2. Monophonic
If S contains two nonadjacent vertices u and w, we show by induction on n that any every vertex v in G = Qn lies in an induced path between u and w.
Note that Qn can be obtained by adding a perfect matching between two copies A and
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$$A \prime$$
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of Qn−1 in such a way that every vertex x in A is linked to its copy
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$$x \prime$$
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in
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$$A \prime$$
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. Suppose first that u and w are in A and v in
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$$A \prime$$
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; in this case we can construct an induced path going from u to
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$$u \prime$$
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, then from
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$$u \prime$$
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to
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$$w \prime$$
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passing through v (using induction), and finally from
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$$w \prime$$
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to w. If u, w, and v are in A then, by induction, there is an induced path from u to w through v entirely contained in A. If u is in A and w in
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$$A \prime$$
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then there is, by induction, an induced path from the vertex in the same copy of v, say u, to v; from v the path continues to
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$$v \prime$$
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and, finally, to w. Hence the following:
Theorem 5 In the monophonic convexity, if S contains two nonadjacent vertices then
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$$I ( S ) = H ( S ) = \;V ( G )$$
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.
Note that if S is a clique then
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$$\vert S \vert = 2$$
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, because the clique number of Qn is two. In this case, by Theorem 2, S is convex. Hence the following:
Theorem 6
Let
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$$S \subseteq V ( G )$$
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and
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$$z \in V ( G )$$
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. In the monophonic convexity, z is in I(S) if and only if either S contains two nonadjacent elements or S = {z,x} for a vertex x adjacent to z.
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$${{ \textbf{\textit{P}}}_{ \textbf{\textit{3}}}}$$
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and
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$${ \textbf{\textit{P}}}_{ \textbf{\textit{3}}}^*$$
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convexities. As in Section 3.1, checking if a vertex v belongs to I(S) amounts to checking if there are two neighbors of v that belong to S. Hence the following:
Theorem 7 P3-id and
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$$P_3^*$$
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-id are solvable in time polynomial in n and
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$$\vert S \vert$$
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.
3.3. convex hull determination
As seen in Section 3.2, in the geodetic and monophonic convexities we have that I(S) = H(S) for any S.
Theorem 8 geodetic–chd and monophonic–chd are solvable in time polynomial in n and
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$$\vert S \vert$$
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.
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$${{ \textbf{\textit{P}}}_{ \textbf{\textit{3}}}}$$
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and
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$${ \textbf{\textit{P}}}_{ \textbf{\textit{3}}}^*$$
\end{document}
convexities. In such convexities, we also have that
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$$H ( S ) = {Q_{n \prime }}$$
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, where
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$$n \prime = n - k$$
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and k is the number of agreeing positions considering all the strings in the input set S.
Theorem 9 P3-CHD and
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$$P_3^*$$
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-CHD are solvable in time polynomial in n and
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$$\vert S \vert$$
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.
3.4. convexity number
3.4.1. Geodetic
In the geodetic convexity, if S is isomorphic to
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$${Q_{{{ \log }_2} \vert S \vert }}$$
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then S is convex, by Theorem 1. Suppose S is convex and has size >2n−1. Then there is at least one vertex outside a hypercube of size 2n−1, which implies that
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$$\vert S \vert = {2^n} = \vert V ( G ) \vert$$
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. Hence the following:
Theorem 10 In the geodetic convexity,
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$$c ( G ) = {2^{n - 1}}$$
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.
3.4.2. Monophonic
By Theorem 2, a set S strictly contained in V (G) is monophonically convex if
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$$\vert S \vert = 1$$
\end{document}
or
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$$\vert S \vert = 2$$
\end{document}
with two adjacent elements. Now, suppose
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$$\vert S \vert \ge 3$$
\end{document}
. Then, S contains a pair of nonadjacent vertices, and, by Theorem 5, the only convex set in this case is V (G). Hence the following:
Theorem 11 In the monophonic convexity, c(G) = 2.
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$${{ \textbf{\textit{P}}}_{ \textbf{\textit{3}}}}$$
\end{document}
and
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$${ \textbf{\textit{P}}}_{ \textbf{\textit{3}}}^*$$
\end{document}
convexities. The arguments used previously for the geodetic convexity also apply to the
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$${{ \textbf{\textit{P}}}_{ \textbf{\textit{3}}}}$$
\end{document}
and
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$${ \textbf{\textit{P}}}_{ \textbf{\textit{3}}}^*$$
\end{document}
convexities.
Theorem 12 In the
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$${{ \textbf{\textit{P}}}_{ \textbf{\textit{3}}}}$$
\end{document}
and
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$${ \textbf{\textit{P}}}_{ \textbf{\textit{3}}}^*$$
\end{document}
convexities,
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$$c ( G ) = {2^{n - 1}}$$
\end{document}
.
3.5. interval number
3.5.1. Geodetic
Consider a pair
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$$s , s \prime$$
\end{document}
of complementary strings, that is,
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$${s_j} = 1 - {s \prime _j}$$
\end{document}
for any
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$$j \in \{ 1 , \ldots , n \} $$
\end{document}
. Then s and
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$$s \prime$$
\end{document}
are endpoints of a diametral path in G, and any z lies in a shortest path between s and
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$$s \prime$$
\end{document}
, that is,
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$$S = \{ s , s \prime \} $$
\end{document}
is an interval set. Hence the following:
Theorem 13 In the geodetic convexity, in(G) = 2.
3.5.2. Monophonic
Recall from Theorem 5 that, in the monophonic convexity, if S contains two nonadjacent vertices then
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$$I ( S ) = H ( S ) = \;V ( G )$$
\end{document}
. Hence the following:
Theorem 14 In the monophonic convexity, in(G) = 2.
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$${{ \textbf{\textit{P}}}_{ \textbf{\textit{3}}}}$$
\end{document}
and
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$${ \textbf{\textit{P}}}_{ \textbf{\textit{3}}}^*$$
\end{document}
convexities. In such convexities, S is an interval set of G if and only if every vertex outside S has at least two neighbors in S. Suppose G is formed by two copies
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$$A , A \prime$$
\end{document}
of Qn−1 joined by a matching as previously described. Also, suppose that A is formed by two copies A1, A2 of Qn2, and, similarly,
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$$A \prime$$
\end{document}
by copies
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$${A \prime _1} , {A \prime _2}$$
\end{document}
, where every vertex of Ai is matched with a vertex of
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$${A_i}^ \prime ,\, i = 1 , 2$$
\end{document}
. It is not difficult to see that
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$$S = V ( {A_1} ) \cup V ( {A \prime _2} )$$
\end{document}
is a minimum interval set of G where every vertex outside S has exactly two neighbors in S. Since
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$$\vert V ( {A_1} ) \vert = \vert V ( {A \prime _2} ) \vert = {2^{n - 2}}$$
\end{document}
, we have the following:
Theorem 15 In the
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$${{ \textbf{\textit{P}}}_{ \textbf{\textit{3}}}}$$
\end{document}
and
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$${ \textbf{\textit{P}}}_{ \textbf{\textit{3}}}^*$$
\end{document}
convexities, in(G) = 2n−1.
3.6. hull number
Recall from Section 3.5 that, in both the geodetic and monophonic convexities, we have in(G) = 2. In addition, in such cases, an interval set is also a hull set. Hence the following:
Theorem 16 In the geodetic and monophonic convexities, hn(G) = 2.
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$${{ \textbf{\textit{P}}}_{ \textbf{\textit{3}}}}$$
\end{document}
and
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$${ \textbf{\textit{P}}}_{ \textbf{\textit{3}}}^*$$
\end{document}
convexities. In the case of the
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$${{ \textbf{\textit{P}}}_{ \textbf{\textit{3}}}}$$
\end{document}
and
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$${ \textbf{\textit{P}}}_{ \textbf{\textit{3}}}^*$$
\end{document}
convexities, we prove that if n ≥ 2 then hn(G) = n.
We first prove that there is a hull set S of G such that
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$$\vert S \vert \le n$$
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. If n = 2, this is trivially true. If n > 2, suppose that G is formed by two copies
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$$A , A \prime$$
\end{document}
of Qn-1 such that every x in A is matched with
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$$x \prime$$
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in
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$$A \prime$$
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. By induction, there is a hull set SA of A such that
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$$\vert {S_A} \vert \le n - 1$$
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. Let
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$$S = {S_A} \cup \{ u \prime \} $$
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, for a vertex
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$$u \prime$$
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in
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$$A \prime$$
\end{document}
arbitrarily chosen. Note that every vertex
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$$w \prime$$
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adjacent to
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$$u \prime$$
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in
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$$A \prime$$
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is adjacent to two vertices in
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$$H ( {S_A} ) \cup \{ u \} $$
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, namely
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$$u \prime$$
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and w. Thus,
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$$N [ u \prime ] \subseteq H ( S )$$
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. Now every vertex in
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$$A \prime$$
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at distance two from
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$$u \prime$$
\end{document}
is adjacent to at least two vertices in
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$$H ( {S_A} ) \cup N [ u ]$$
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. Since
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$$A \prime$$
\end{document}
is a connected graph, this process continues until all vertices of
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$$A \prime$$
\end{document}
are included in the convex hull of S. Hence S is a hull set of G and
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$$\vert S \vert \le n$$
\end{document}
.
Now we prove that any hull set S of G satisfies
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$$\vert S \vert \ge n$$
\end{document}
. Note that, for any S, H(S) consists of a union of disjoint hypercubes
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$${Q_{{n_1}}} , {Q_{{n_2}}} , \ldots , {Q_{{n_k}}}$$
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such that
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$$\max \{ {n_i} \} \le \vert S \vert$$
\end{document}
(a single-vertex subgraph is considered in this study as a hypercube Q0). Thus, S is a hull set if and only if k = 1 and n1 = n. If contains fewer than n strings then S cannot be a hull set. Hence the following:
Theorem 17 In the
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$${{ \textbf{\textit{P}}}_{ \textbf{\textit{3}}}}$$
\end{document}
and
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$${ \textbf{\textit{P}}}_{ \textbf{\textit{3}}}^*$$
\end{document}
convexities, hn(G) = n.