We consider the stationary Stokes problem in a three-dimensional fluid domain with non-homogeneous Dirichlet boundary conditions. We assume that this fluid domain is the complement of a bounded obstacle in a bounded or an exterior smooth container Ω. We compute sharp asymptotics of the solution to the Stokes problem when the distance between the obstacle and the container boundary is small.
In this paper, we consider the 3D-Stokes problem
in a fluid domain . Without restricting the generality, we set the viscosity of the fluid to 1. We assume that is the complement of a smooth simply-connected bounded domain inside a container Ω. The container Ω is either a relatively compact simply-connected smooth open set or the exterior of a simply-connected smooth compact set . In both cases, it has a smooth compact connected boundary. We complete then (1)–(2) with boundary conditions:
where does not prescribe any flux through the container boundary:
If Ω is an exterior domain, we add a vanishing condition at infinity:
With the above assumptions on the boundary data it is classical that system (1)–(4) (+(6)) admits a unique classical solution (the pressure p being unique up to a constant), see [8] for instance. Our aim in this paper is to give a sharp description of the solution to the Stokes problem (1)–(4) (+(6)) when the distance betweenandis small.
Computing such asymptotics is an important issue related to the modeling of solid-body motion inside a viscous fluid. The typical configuration we have in mind is that (resp. and ) is a (are) moving solid body (bodies) inside the container Ω (in the whole space) which is filled by a viscous incompressible constant-density fluid. A typical issue is then to determine whether the fluid viscosity prevents the moving body from touching other solid boundaries (i.e. the boundary of the container or the boundary of the other solid body) and more generally to measure the influence of the viscosity on the close-contact dynamics of . To this end, one remarks that, when a solid body is about to collide another solid boundary with moderate relative velocity, the fluid Reynolds number tends to 0 in the gap so that a stationary Stokes system is sufficient to predict the force and torque exerted by the fluid on the moving body. With this particular application in mind, several authors consider the free-fall of a sphere above a ramp [4,5,7,18,19] in a Stokes fluid. Explicit values for the solution to the Stokes problem (1)–(4) (+(6)) and the associated force and torque are provided. A formal lubrication approximation is also proposed in [6,11] which generalizes these formulas to arbitrary configurations. In the limit regime where there is contact, solutions to the Stokes problem are also computed in [17] under further assumptions on the boundary data (broadly, the boundary data has to vanish sufficiently where there is contact). Related computations for a perfect fluid are provided in [2,15,16].
In this paper, we fill the gap between the explicit formulas of [4,5,7,18,19], the formal asymptotics of [6,11] and the analysis in [17]. We justify rigorously lubrication approximation in the spirit of [1,3]. Compared to these latter references, we are interested inhere in fluid films that do not vanish uniformly in their widths. This fact leads to severe new difficulties. First, the lubrication scaling acts on coordinates in both tangential and orthogonal directions to the boundaries (see (9)–(12)). Second, the asymptotic pressure and velocity-fields yielding from the formal lubrication approximation are defined on an asymptotic fluid domain which is not simply related to the fluid-domain for a given positive body/boundary distance h. Consequently, in order to compare the values of the solution to the Stokes problem with its asymptotic value, we introduce an intermediate velocity-field which embeds the lubrication approximation in the effective fluid-domain (see Section 4.1). The construction of this intermediate velocity-field is an important step of our analysis. Indeed, the intermediate velocity-field is a key-ingredient in order to extend the computations on the close-contact dynamics of bodies in a Stokes fluid to more complicated models: Navier–Stokes/Newton models or Navier–Stokes/elasticity models. This fact has already been shown for the Navier–Stokes/Newton model in simple configurations (see [9,12–14]). We believe our approach extends to other incompressible models (for instance to the case of potential flows as in [16]). However, the incompressibility condition is crucial to our computation and the extension to the compressible case is completely open.
To fix ideas, we make more specific the geometry of the gap between and . We introduce a set of Cartesian coordinates and the corresponding cylindrical coordinates. These coordinates are associated with two orthonormal basis of denoted by and , respectively. We consider that, in a neighborhood of the origin, Ω and satisfy:
Here are given positive parameters. The first one measures the distance between and , the second one is a characteristic length on which parametrizing the boundaries of Ω and by -variables is relevant. The two functions and are smooth on and we assume throughout the paper that they satisfy the following assumptions:
,
there exists such that (in the sense of symmetric matrices)
We complement these local assumptions in with a global one concerning and outside :
The parametrizations (7) and (8) together with assumptions (A1)–(A2)–(A3) are paradigmatic of what we call a “single non-degenerate contact”. Indeed, considering that is a translating particle inside the container Ω amounts to let the parameter h depend on time. Assumption (A3) implies then that a contact between and may only hold in . Assumption (A2) yields that the contact in is unique and non-degenerate i.e. when the “vertical” distance vanishes in 0 only and with minimal vanishing order. We emphasize that, in the smooth case we consider here, the uniform boundedness we require in (A2) reduces to assuming that
up to restrict the size of L and change the value of . In this “single non-degenerate contact”-case, the assumptions (7)–(8) together with (A1) do not restrict the generality: they only amount to choose the origin of coordinates in the only point of realizing the distance between and , and to choose the system of coordinates so that the common normal to and , in the pair of points realizing the distance between and , is .
Our aim is to compute the asymptotics of the solution to the Stokes problem (1)–(4) (+(6)) for a given boundary condition in the geometry depicted above under the further assumption that h is small and other parameters are of order 1. To introduce our main result, we recall the main steps of the formal computations in [6] for the case where is a sphere of radius S and with a sphere of radius R. First, given the shape of the aperture between both spheres, one looks for a solution that reads
in the aperture between the spheres. The parameter α is chosen depending on the values of . For instance, if with , one chooses . We proceed with this particular case. We denote with tildes the new space variables
These new coordinates belong to the set that “converges” (when ) to
Substituting ansatz (9)–(12) into (1)–(2) yields:
completed with boundary conditions:
The pressure is normalized by assuming that it vanishes at infinity. Introducing , the unique solution to this problem reads , with:
and where is the unique solution to
Herein, we justify these formal computations rigorously. A (nonetheless formal) statement of our main result reads as the following theorem.
Assume (A1)–(A3) are in force andsatisfies (5). Letandbe given by:Whenwhileremain of order 1, the main contribution to the velocity-field of the solutionto the Stokes problem (1)–(4) (+(6)) is given bywithin the aperture domain, and where q is the unique solution towith.
We introduce here the notations and ⊥ for the components of a vector v that are respectively parallel and normal to the tangent space to in the origin. Corresponding decomposition of ∇ are denoted by and . We keep this convention in what follows. Our geometric assumptions imply that and are tangent to in the origin. Hence, the derivatives and are well defined. Even though the result concerns an asymptotic behavior when the value of this parameter is fixed in all computations. For this reason, we do not let the parameter h appear in most of our notations (such as the fluid domain , the distance function γ …).
A more quantitative statement of the above theorem is given in next section. In particular, we make precise for which norms the extracted contribution is the dominating term, the size of remainder terms and the dependencies w.r.t. , , , . We prove this result by
computing a priori estimates on the pressure q as constructed in this statement (in the regime );
relating the difference between the exact solution u to the Stokes problem and (an extension of) v to the obtained estimates on the pressure q.
As a corollary, we obtain that the leading order in the asymptotics of the Stokes solution is given by the first-order expansion of the boundary data in the origin. This dependence occurs through a pressure solution to a simpler problem but still not explicit. We explain in next section that in some special case (when is a sphere and with a sphere) we can compute accurate informations on the pressure and get explicit expansion of the Stokes solution w.r.t. h and the boundary data , , .
In the set of assumptions we introduced up to now, we enforced the boundary condition to vanish on . We can always reduce asymptotic computations with general Dirichlet boundary conditions to this case. We also emphasize that the computations, that we present here in the “single non-degenerate contact” case, extend to general “non-degenerate contacts”. A general non-degenerate contact would correspond to the case where the moving solid may collide in several points satisfying assumption (A2). There would then exist at most a finite number of “contact points” that might be treated separately as “non-degenerate isolated contacts”. The linearity of the Stokes problem ensures that the exact solution behaves as the sum of the asymptotic solutions that we compute in the vicinity of each contact point. Previous calculations due to Starovoitov show that these “non-degenerate isolated contacts” are the only remaining ones to rule out in order to show that no contact between solid bodies occur in a Stokes or a Navier–Stokes fluid (see [20]).
The outline of the paper is as follows. In next section, we recall the classical theory for solving the Stokes problem (1)–(4) (+(6)) and give a quantitative statement of our main results, see Theorems 4 and 5. In Section 3, we study the properties of the problem (18)–(19). We compute estimates satisfied by the solution q with respect to the data and compute the divergence-rate of q when . One particular feature of the estimates we obtain is that they are “uniform” w.r.t. the distance h. The last two sections are devoted to the proofs of Theorems 4 and 5, respectively.
Quantitative statement of main results
In this section, we recall function-spaces and existence results for problem (1)–(4) (+(6)). We give then a quantitative statement of our main result. We conclude by exhibiting two criterions which measure whether a velocity-field is a good approximation of a solution to the Stokes problem or not.
Solving the Stokes problem
We first recall the way the system (1)–(4) (+(6)) is tackled in [8]. Let denote:
and ,
V (resp. ) the completion of (resp. ) endowed with the norm:
This makes (resp. ) to be a Hilbert space endowed with the scalar product:
In the terminology of [8], our space V (resp. ) is a closed subspace of (resp. ), see [8, p. 80]. In particular, applying [8, Theorem II.6.1(i), (II.6.22)] we have that V embeds in so that . This entails that vanishes at infinity in a weak sense, if required, and has a well-defined trace . In particular, for arbitrary , we might define the affine-subspace of V:
We recall that this set is not empty as soon as prescribes no flux through and that we have the identity (see [8, Theorem II.7.1(i)]).
Following [8] we introduce the definition of generalized solution to (1)–(4) (+(6)).
Let we call generalized solution to (1)–(4) (+(6)) any such that
And we have the classical theorem (see [8, Theorem V.2.1 and Theorem V.1.1]).
Given, such that:there exists a unique generalized solutionuto (1)–(4) (+(6)). Moreover,
there existssuch that (1) holds in the sense of distributions;
ifthere holds.
A consequence of this result is that generalized solutions with smooth data are classical solutions. As we only consider this particular case throughout the paper, we drop the adjective “generalized” in what follows. Also, we abusively call solution to (1)–(4) (+(6)) a velocity-field u, even though a solution to the Stokes problem is a pair velocity/pressure .
Main results
The main contribution of this paper is the following theorem.
Assume (A1)–(A3) and boundary conditionsatisfies (21). Let denote bythe unique associated solution to (1)–(4) (+(6)). If, there existsand a constantsuch that:
If the distance function γ is moreover radial, we have the following improvement of the second assertion:
We remark that u and v are bounded uniformly in h as along as this parameter ranges a compact subset of . Consequently, this theorem brings relevant informations in the limit . It shows in particular that even though the fluid is incompressible (so that the Stokes problem is non-local), when h goes to 0 the leading order of the velocity-field is completely fixed by the boundary conditions and the geometric properties of the boundaries in the aperture . It will be clear from the example given below that the velocity-field v we exhibit is larger than the remainder in the sense of the V-norm. We mention that our first interest in this problem was to compute the diverging term in the case of spheres. As the remainder is bounded in this radial case, we did not look for a more complicated expansion of the solution. Nevertheless, a corollary of our method is the construction of the linear problem on which could rely the computation of a full expansion of the solution in terms of h. However, we would only describe the solution in the gap and the computation of -terms would require another tool enabling to compute the expansion of the solution outside the gap also.
To highlight the relevance of the above theorem, we detail the case where is a sphere and with a sphere, as in the computations in the Introduction. Keeping the convention that has radius R and has radius S, we have that, close to the origin, the functions and satisfy:
and also that γ satisfies:
with given by:
In this case of spheres, we obtain the following theorem.
Given a boundary conditionsatisfying (21) there exists a constantdepending only on R, S so that if, the unique solutionto the associated Stokes problem (1)–(4) (+(6)), satisfies:
The norms that we compute in this theorem are related to the forces and torques exerted by the fluid flow on the spheres. Indeed, assume that the sphere is moving with a rigid velocity and that we want to compute the forces and torques exerted by a Stokes flow on when the distance to the other sphere is small. By symmetry, we can assume that is moving with a rigid velocity and compute the force and torque exerted on . Then, we recall that the set of rigid velocities is a 6-dimensional vector space whose elements are characterized by a translation and angular velocity (computed with respect to the origin for simplicity). Let denote by (resp. ) the solutions to the Stokes problem on with elementary translational (resp. rotational) boundary conditions
Due to the linearity of the Stokes problem (1)–(4) (+(6)), the solution associated with boundary condition is then a combination of the and . Furthermore, straightforward integration by parts yield that the jth component of the force exerted by the flow on reads:
(here ν stands for the normal to pointing towards ). If , we obtain:
and the asymptotic behavior or when yields by applying the above theorem. By standard algebraic formulas this identity is generalized to all components of the forces and torques associated with any rigid velocity . Then, one can see the asymptotic expansions we compute in Theorem 5 as a justification and an improvement of the asymptotic values for the matrix provided in [6, Section 7] (see Eq. (7.6)).
Two approximation criterions
We conclude this section by providing two criterions which will enable us to measure the distance between an approximation v and the exact solution u of the Stokes problem (1)–(4) (+(6)).
First, we recall that one way to prove the existence part of Theorem 3 is to construct and to remark that we have . Existence and uniqueness of a generalized solution then yields from an application of the Stampacchia theorem. This proof entails the expected result together with the following variational characterization.
Givensatisfying (21), the solutionuto (1)–(4) (+(6)) realizes:
As a consequence, given , and the generalized solution to (1)–(4) (+(6)), we have conversely that any satisfies:
This enables to compute many bounds from above for by choosing approximations v. The more relevant the approximation, the sharper the bound. To control the distance between an approximation v and the exact solution u we have more precisely the following proposition:
Letsatisfy (21) and denote bythe solution to (1)–(4) (+(6)). Givenwe denote:i.e.is the best constant C such that:Then, there holds:
The proof is standard. For completeness, we recall it briefly. There holds:
Applying (20) to , we obtain:
Introducing then a sequence such that in V, we have:
where, for all , there holds:
Again, as , we apply definition (24) of . This entails:
and, in the limit :
This ends the proof. □
We emphasize that in the statement of this criterion there is no geometrical constant in front of in (25). This is particularly important as we want to consider the influence of the geometry on the relevance of the approximation v. Actually, these geometrical dependencies are hidden in the computation of .
Preliminary results on the lubrication problem
In this section, we consider the two-dimensional divergence problem:
We restrict to source terms which have the special form:
The weight is computed with respect to and :
with a small but positive distance h. The assumptions (A1)–(A3) are in force. It is standard that, since γ is smooth and bounded from below by a strictly positive constant, there exists a unique smooth solution ϖ to (26)–(27). Our aim is to compute estimates on quantities of the form:
with explicit dependencies in the data f, the distance h, and . In these estimates will appear constants depending directly on γ, , . We state the definition of these constants as a lemma.
There exist constantsdepending onandonly andsuch that there holds:and, for:
The proof of this lemma is an obvious consequence of (A1)–(A3) and is left to the reader. We remark that the constants and are related to the constant appearing in assumption (A2). Assumption (A1) together with (31) imply there exists a constant K depending on and such that:
With these conventions, the main results of this section are the following propositions. We first write two weighted first-order estimates on the solution ϖ of (26)–(27) depending on the behavior of the data and (recall that f is given by (28)) in the origin.
Assume that the data,satisfy:Let. There exists a constantdepending on,,and n for which:
Let. There exists a constantdepending on,,and n for which:
ifwe have:
ifthere holds:
ifwe have:
if, there holds:
We emphasize that the constants do not depend on h. In particular, the latter proposition implies that, when vanishes, all quantities:
remain bounded when h goes to 0. We complement the study with higher order estimates away and around the singularity point .
Given a integerand, there exists a positive constantdepending only on L, ε, k,,,, with, for which ϖ satisfies:
Let,and denote. There exists a constantdepending on k, n,,,, with, such that:
In the remainder of this section, we first give proofs for these propositions. We then conclude by showing that the first-order estimates are optimal in the case of sphere.
First-order estimates: Proofs of Propositions 9 and 10
System (26)–(27) is associated with the weak formulation:
Hence, to construct solutions, one introduces the bilinear form:
A definition for weak solution to (26)–(27) then reads as the following definition.
Thanks to (29)–(31), defines a coercive continuous bilinear form on . Existence and uniqueness of a weak solution to (26)–(27) yields as a straightforward application of the Stampacchia theorem. Given our regularity assumptions on the distance function γ, classical results on divergence problems apply so that this weak solution is smooth on and satisfies (26)–(27) in a classical sense (see [10, Chapter 8]). All the estimates in [10, Chapter 8] depend a priori deeply on h so that an alternative approach is required.
In the proofs below, we denote with K a constant which is important to our computations and shall put in brackets its relevant parameters (such as , ). These constants may differ from line to line. Most of these constants shall also depend on the parameter L but we include this tacitly. Notations C are used for generic constants that depend only on L or on other parameters that are irrelevant to our computations. Again, they may differ from line to line. Regarding constants K, it might appear that a constant depend on and for . In this case, we have that the constant K depends on the k-first derivatives of and and also on the j-first derivatives of and . We shall simplify K then into a function depending only on the l-first derivatives of and with , i.e., on .
From now on, we fix data and denote the associated (weak) solution ϖ. The first step of the proofs is the following preliminary lemma.
Given, there exists a constants.t. ϖ satisfies:
Given , as γ is a positive function, explicit computations yield that:
Introducing the bound (30) on , we deduce that:
Now, for any , integrating by parts and applying Hölder inequality yields:
Applying then (44) to bound the first term in the right-hand side of this last inequality, we obtain:
We multiply now (26) with . This yields:
We compute separately the RHS and the LHS of this identity. If the last term on the LHS is positive. If , we remark that ϖ vanishes on and apply (46) to ϖ. This entails:
We note here that, since the factor appearing in the right-hand side of this identity is positive. The fact that this factor changes sign when α crosses 2 makes this proof irrelevant for .
Concerning the RHS, we have first, applying (45) and (46) (with and noting that ), that, for arbitrary , there holds:
Similarly, by applying (44), (45) and (46) (again with ) and (33), we obtain that, for and arbitrary , there holds:
This yields finally that we have, for arbitrary :
We replace finally the right-hand side and left-hand side of (47) with (49) and (48) and obtain the expected result by choosing ε sufficiently small depending on α. □
We are now in position to prove Propositions 9 and 10.
Because γ is bounded by on , it is sufficient to prove (35) in the case . Under the further assumption (34), there holds (from the two-dimensional embedding for arbitrary )
for .
Applying then Lemma 14 to ϖ with , we obtain:
Here we call (50)–(51) and (31) to obtain:
This ends the proof. □
Because γ is bounded by on , it is sufficient to prove (39) and (38) in the cases , and .
Applying Lemma 14 with , we have, with a constant depending on , , and n:
Here, we note that so that . Hence, we might fix such that . Introducing the conjugate exponent, we get:
In the right-hand side of this last line, we note that standard 2D-Sobolev imbeddings yield
and that, from (31):
as . This ends up the proof in the last case.
Applying the embedding , we have:
The remainder of the computation follows the line of the previous case. Applying Lemma 14 with , we have, with a constant K depending on the same quantities:
Again, we apply Lemma 14 with , and apply the embedding . This yields with similar computations as previously:
We conclude with similar arguments, applying Lemma 14 with , and the embedding .
This ends the proof. □
Higher order estimates: Proofs of Propositions 11 and 12
We compute now estimates involving with . We start with estimates away from the origin.
This proposition follows from the classical regularity theory for elliptic problems, as developed in [10]. Indeed, fix and . Applying Proposition 10 with , and combining with (31), we obtain for a constant K which depends on , , and L that
As on , we deduce from this inequality (applying the variant of Poincaré inequality given in [8, Exercise II.5.13]) that there exists a constant so that:
Then, we note that the operator is uniformly elliptic on with ellipticity constant depending only on and ε. Finally, applying [10, Theorem 8.8, p. 183 with Theorem 8.12, p. 186] if or [10, Theorem 8.10, p. 186 with Theorem 8.13, p. 187] if implies that there exists a constant depending on ε, and so that:
where we applied (53) to reach the last line. □
This proposition is a tool for computing the traces of derivatives of ϖ on . With this consideration, we obtain Proposition 12.
To prepare the proof, we mention that the chain rule together with (32) yields that for any integer there exists a constant depending on , and , for which:
This inequality no longer holds when . Again, this is the reason for our lemma to hold only for values of the parameter k below 6.
We prove now by induction on k for fixed that there holds:
“there exists a constant depending on k, m, , , , with , such that, denoting by :
The case is obvious. To prove the induction argument, we fix and introduce a (homogeneous) differential operator of order having constant coefficients. Applying to (26) yields:
where:
We multiply (56) with . After integration by parts, this yields:
where:
We bound the first term in by applying trace theorems and Proposition 11: there exists a constant (depending on and also on L) for which
For the second term, we apply (32) and a Hölder inequality:
To bound the last term, we note that . Consequently, applying the induction assumption, we obtain:
As for , we distinguish between two cases. If we have that so that a standard Hölder inequality yields, with the induction assumption:
Whereas, if so that in particular, we introduce arbitrarily the missing powers of γ and recall (32)–(33):
where so that:
and
Hence a Hölder inequality yields that:
To treat the last terms, we expand the differential operator and apply (54) yielding that there exists also a constant for which:
Consequently, we bound similarly as above by applying trace theorems and Proposition 11:
For the other term, we recall (32) and apply the induction assumption. This yields:
We obtain finally that there exists a constant depending on , , and , , for which:
We introduce this inequality into (57) and obtain that:
Given the dependencies of and , , the operator being arbitrary, we obtain the expected inequality for the rank . This ends the proof. □
The case of spheres
We end this section by computing sharp asymptotic expansions of
when γ represents the distance function between one sphere of radius S and another one of radius R. Until the end of this section, we assume that, close to the origin, we have:
Hence, γ depends on only and we have the Taylor expansion:
where and satisfy (22).
Then, we split , where:
Due to the linearity of the divergence problem (26)–(27), the solution ϖ admits a corresponding decomposition: with obvious notations. In this section, we compute separately the asymptotic expansions of the quantities
First, as corresponds to f from which the first orders in the Taylor expansion around 0 are subtracted, we may introduce s.t.:
We have then:
Hence, Proposition 9 entails that, for :
Here and in what follows, we denote by a quantity which depends on and h and is bounded by a constant depending only on R, S, L whatever the value of .
It remains to treat the two cases of and . We remark at once that, for , the associated source term is constant, while, for , the associated source term reads where:
We start with .
Under the assumption that γ is radial and satisfies (58), there holds:
By linearity, we only treat the case . Under our symmetry assumptions, the unique solution to (26)–(27) with is certainly a radial function and explicit computations yield that:
Consequently, we have:
At this point, we note that
with for all . Consequently, introducing small enough so that we might expand γ in power series, we have:
where explicit computations yield:
Finally, we obtain:
We end this section with the case of an -like source term.
Assume that γ is radial and satisfies (58). Given a source term of the formon, there holds:
Up to shift θ with a phase and call the linearity of our problem, we prove the above result in the case and . Then, the proof is divided into 3 steps.
(Reduction to an ode).
Under our symmetry assumptions, the unique solution to (26)–(27) reads where is the unique solution to the ode:
The boundary condition in is the translation of on while the boundary condition in is derived from the condition that:
We note that (61) rewrites:
(Construction of an approximate solution).
We introduce then q the unique solution to an auxiliary problem. The construction and properties of this auxiliary function are stated in the following lemma whose proof is postponed to the Appendix.
Given, there exists a uniquesolution toFurthermore, we have the asymptotic description:wherefor.
With that auxiliary function at-hand, we set:
Introducing , we obtain by substitution that is a solution to
where
Consequently, is an -solution to:
We note that, for , there holds:
Replacing with its value and noticing that because of (63), this entails:
We bound the first integral on the right-hand side by changing variable . This yields:
Given the asymptotic expansion of q this entails:
In particular we obtain finally that:
(Computing the distance between ϖ and ).
We introduce the difference . It is the solution to:
Multiplying (65) with , we obtain, after integration by parts:
On the left-hand side of this identity, we have:
as on . On the right-hand side, we obtain the bound above:
where, after integration by parts:
for arbitrary . At this point, we remark that, as γ and share the same (non-vanishing) Taylor expansion up to the second order, we have, with a constant K depending only on R, S:
Recalling (32) to bound and (64) we obtain:
and finally, for arbitrary positive ε, we have:
Similarly, we bound :
where there is a constant K depending only on the characteristics of γ for which
Hence, we have:
and finally, for arbitrary , there holds:
Introducing the above computations of the left-hand side and right-hand side into (67), noticing that
thanks to (63), we obtain, choosing ε sufficiently small:
(Conclusion).
We are now in position to compute the asymptotics of
Indeed, there holds:
As previously, we bound so that recalling (64) with we have:
Then, (68) implies:
We conclude with similar arguments and applying Proposition 10 in case (here ϖ is a solution to (26)–(27) with a special and ):
Hence, there holds:
because of (64). This ends the proof of Proposition 16. □
Proof of Theorem 4
In this section, we complete the proof of Theorem 4. We first introduce some notations:
is a truncation function which vanishes outside . Namely, we set
with satisfying
we recall, that given , we denote:
is a smooth subdomain of which does not depend on h and satisfies:
We note that such an exists as, thanks to assumptions (A2) and (A3), there exists depending on δ and such that, whatever the value of there holds
Construction of asymptotic approximation
Let fix one boundary condition satisfying (21). At this step, we explain how to construct a velocity-field which shall approximate the solution to the Stokes problem with boundary conditions in the regime .
Let split into its tangential and normal parts (according to the tangent space in the origin):
We introduce the unique solution to
We recall that the data , and are smooth so that we have existence of a unique solution to this equation satisfying:
Second, we construct an auxiliary pair velocity-field/pressure in the aperture domain. We denote:
and
for . We note that this velocity-field vanishes outside . We keep notations to denote its trivial extension to in what follows.
Combining (70) with (69)–(72)–(73), we obtain that:
and has support in ,
on ,
on ,
on .
All properties satisfied by are obvious but:
This property is a consequence of solution to (69). We warn the reader that, to check this implication, one cannot commute the divergence and integral operators prior to taking the trace on . Indeed, the differential operator does not include only derivatives parallel to the boundary so that one has to expand the differential operator inside the integral to perform this computation.
The internal velocity-field does not match the boundary condition outside (unless vanishes). As we expect no singular behavior of the exact solution to the Stokes problem far from the singularity, we extend the approximation in a simple way outside . Precisely, we define
As and is smooth, we have that . Moreover, the properties of the boundary values of that we mentioned above ensure that vanishes on . Consequently, we might extend by 0 to , defining in this way a smooth function. Then, we denote the unique solution to:
This solution indeed exists as:
As and are smooth we also have that is smooth on and vanishes on . Hence, the trivial extension of to (that we still denote for simplicity) satisfies:
is continuous piecewise smooth and has support in ,
on ,
on ,
on .
Our asymptotic approximation reads then
Even though the vector-field is important in order to obtain a velocity-field that matches the boundary conditions on the whole , this external velocity-field does not contain any information on the way the velocity-field diverges when h is small. Indeed, we have the following lemma.
There exists a constant K depending on,,and δ (introduced in (A3)) such that:
Indeed, as solution to the Stokes problem on , the exterior velocity-field satisfies
where the constant depends only on which depends itself on the geometry of away from the singularity and δ. Moreover, recalling that vanishes in , we might construct a function such that on and on . We have then, introducing a lifting of on the whole Ω:
As remains away from the singularity, we might bound from below γ by a constant depending only on on and apply the explicit formulas for to obtain the following bounds:
We now wish to apply Proposition 11 to in order to yield a constant that bounds its -norm by something which does not depend on h. However, one term in the right-hand side of (69) depends on h. To avoid this difficulty we expand with pressure field components defined as respective solutions to:
and
In particular, we remark that is a solution to (26)–(27) with a source term f given by (28) associated with
and that is a solution to (26)–(27) with a source term f given by (28) associated with
Hence, we apply Proposition 11 to both and and obtain:
This entails finally:
Main steps of the proof of Theorem 4
We fix now satisfying (21) as in the assumptions of Theorem 4. We split this boundary condition in
with:
Note that, straightforward computations entail:
So, we might define the solutions of Stokes system (1)–(4) (+(6)) as given by Theorem 3 for boundary data , , . We denote these solutions , , , respectively. We also introduce the asymptotic approximations:
Let denote . Then, as is constant, we have that
so that the pressure associated with satisfies (18)–(19) and, consequently, satisfies (16)–(17) in . To complete the proof, it remains to compute
Next subsection is devoted to the computation of and the following one to . In particular, the proof of Theorem 4 is completed by applying Proposition 19 and Proposition 21 in the general case and by applying Propositions 19, 22 and 23 in the radial case.
Asymptotics of
We start with the remainder term . Keeping notation for , we prove the following proposition.
There exists a constant K depending on, δ,,,and L such that, if, there holds:
We recall that thanks to the variational characterization Proposition 6, realizes the minimum of V norms among divergence-free velocity-fields w satisfying the same boundary conditions as (i.e. with our notations). By construction, we have so that the above proposition is a consequence of the lemma.
There exists a constant K depending on, δ,,,and L for which, if:
We drop index R in v for the whole proof. We recall that, by construction, we have where and are computed via (72)–(73) and (74)–(76), respectively. We first apply Lemma 18 showing that we only have to focus on the following contribution of :
Explicit computations show that:
and:
with a constant depending on L. Introducing that, for all , there holds
we obtain that, on , there holds:
Integrating this inequality entails that:
In this last identity, we note that, for :
So, we split again with and defined respectively as the solutions to
and
So we have that is a solution to (26)–(27) with a source term f given by (28) associated with
where we note that . Applying Propositions 11, 12 and 10 to , we obtain that,
with K depending on , , and L.
As for , we remark that it is a solution to (26)–(27) with a source term f given by (28) associated with
In this case, we have that and also that , vanish. Consequently, we are in position to apply Propositions 11, 12 and 9 to , yielding that:
with K depending again on , , and L. Combining the computations for and , and arguing that
we get finally:
with K depending on , , and L.
For the last term on the right-hand side of (82), we add that , implying:
Consequently, going to polar coordinates yields (recall γ satisfies (31) whatever the value of ):
This ends the proof. □
Asymptotics of
We proceed with a first bound on the singular term in the general case (i.e., without structure assumption on γ). We prove the following proposition.
If, there exists a constant K depending on, δ,,,and L such that there holds:
We recall that . It is sufficient to compute a constant K (independent of h) such that, if , for all , we have:
(with given by (71)). Indeed, we have then:
Applying Lemma 18 together with the remark that the mapping is linear continuous , we bound the other term by:
with K depending on , , and δ.
We emphasize that and have support in so that:
By construction, we have that:
Consequently, there holds:
For any we can then bound by integrating by parts:
The remainder of the proof follows the line of the proof of Lemma 20. First, we bound and as in the proof of this lemma, this yields:
We obtain then:
and we bound the last integrals on the right-hand side by computing with respect to and applying Propositions 10, 11 and 12 as in the proof of Lemma 20. Note that has only one component because . □
We end this section by considering the case where the aperture admits a cylindrical invariance: . In this case, we introduce and the solutions to the Stokes system associated with boundary conditions:
We note that straightforward computations entail:
So, we have indeed existence and uniqueness of the pairs . We also introduce , the respective approximations of and constructed applying the steps depicted in Section 4.1. We note that, due to the linearity of the Stokes problem and of our construction, we have:
First, remarking that vanishes (so that there is no logarithmic terms yielding from the application of Proposition 10), we reproduce the computations in the proof of the previous proposition and obtain at first the following proposition.
If, there exists a constant K depending on, δ,,,and L such that there holds:
We complete the study of by computing the asymptotics of the most singular term: . We prove the following proposition.
Ifand γ is radial, there exists a constant K depending on, δ,,,and L such that there holds:
As the mapping is continuous , we treat only the case and we drop superfluous index 0.
In this cylindrical case, a particular feature of is that, in the problem solved by the weight γ is invariant by rotation around the origin and the source term is a constant. Consequently, is a radial function and an explicit formula is available (as in the proof of Proposition 15). Up to assume that is also radial, we get that is directed along the radial unit vector . More precisely, we have:
with an explicit formula in the aperture:
Following the proof of Proposition 21 in the previous section, to bound the distance between and , we compute integrals
Again, as in the previous section, explicit computations and integrations by parts yield that:
Here, we introduce that
We plug these identities in the above integrals and integrate by parts. Because of the radial form of (see (87)), we have
This entails:
For the last integral, we bound similarly as in the proof of Lemma 20. Introducing the bounds on , and γ, this entails:
so that, introducing now that and applying Proposition 11:
Applying Propositions 10 and 12 to entails:
Then, we truncate with that vanish on the lateral boundaries of (and is equal to 1 on ) and we obtain that:
With similar arguments as in the proof of Lemma 18 (see (80)), we bound the last term on the right-hand side:
Finally, we apply the formula for which implies, in particular, that:
Hence, introducing that w vanishes on the upper and lower boundaries of , we bound with Cauchy–Schwarz inequalities and a Hardy inequality in the z direction:
We emphasize that the constant C is universal and in particular independent of h. With the explicit formula for we get:
As
we get that, for a constant K depending on and , , there holds:
This ends the proof. □
Proof of Theorem 5
In this last section, we exhibit a particular case where the above informations yield a sharp asymptotic expansion of the quantity:
Throughout this last section, we assume that with a sphere of radius R and that is a sphere of radius S. We recall that we have then:
where and satisfy (22). We fix also a smooth boundary data and denote by u the exact solution to the Stokes problem with boundary condition and the approximation that is constructed in Section 4.1.
We introduce the notations of the previous section: indices 0, 1, , R distinguish the components of and u and . Hence, we have
and a similar decomposition for u. We decompose
Applying Propositions 19, 22 and 23 in the cylindrical case we deduce:
where we keep the convention that landau notations stand for quantities depending on which remains bounded by a constant depending on R, S only for .
The weak formulation of the Stokes problem (remarking that vanishes on ) yields also that:
Hence, we have:
To compute the first integral on the right-hand side of this last equality, we split:
where for we define:
We complete the proof by studying the asymptotics of all these integrals. The first-order terms will yield by computing and .
Study of positive terms
We recall that, by applying Proposition 19, we get at first that
Concerning the other terms, we remark that, by construction so that:
where, reproducing the computations in the proof of Lemma 18 (see (80)), we obtain that, for :
Hence, we get that, for :
Asymptotics of
Let first consider . We drop index 1 in the sequel and we recall that , denoted here by , is constructed as follows:
for , where:
with a suitable truncation function and the unique solution to
From Proposition 11, we obtain first that:
hence we may replace by in computations from now on. Then, it comes from the proof of Proposition 21 (see (86)) that:
We obtain:
Explicit computations yield that, on , there holds:
Consequently, we have that: where (note that the cross-term vanishes by integrating w.r.t. z-variable at first)
We end up the proof by computing the asymptotics of and .
Concerning , we expand, for sufficiently small :
As for , we go back to the computations of Section 3. Indeed, integrating at first with respect to z, we get:
where we apply Proposition 16 to to compute the asymptotics of this last quantity. This yields:
Finally, we obtain:
Asymptotics of
We focus now on and drop index 0 for simplicity. Let first recall that is constructed as:
for , where:
with a suitable truncation function and the unique solution to
We recall further that, in this radial case, we may compute explicitly:
so that
This entails that with:
We assume from now on that for simplicity. We note that we have
so that all terms in the following computations will turn into in the final result.
As in the computations for , from Proposition 11, we obtain first that:
and we replace by . Also, we already computed in the proof of Proposition 23 that
Consequently, we have:
where, due to the incompressibility condition satisfied by :
as remains bounded independently of h away from the origin. We get thus:
with:
Computation of. Replacing the integrand in with its values yields:
At this point, we apply Proposition 15 to yielding:
This entails finally:
Computation of. We proceed with the computation of where:
We first compute by replacing with its values:
We already computed (see the computation of ) that:
so that we obtain finally:
Second, we expand . We have:
Consequently:
After tedious but straightforward computations, we get:
and
Combining computations of and , we obtain:
Asymptotics of cross terms
We proceed with the computation of the asymptotics of cross terms , . We recall that with similar arguments as previously, there holds:
with obvious notations.
Asymptotics of
We first treat the term . For this term, we assume without restricting the generality that is parallel to . As a consequence, we obtain that reads in polar coordinates so that, as a function of it satisfies:
Hence, introducing the rotation matrix,
there holds:
On the opposite, we have that satisfies so that we have the symmetries:
Going to the derivatives, this entails that:
Asymptotics of
By definition, we have:
We introduce:
and, applying that is divergence free, we transform:
In this identity, we integrate by parts the integrals on the first line of the right-hand side yielding:
where we used that
vanishes on ;
in .
We also note that does not depend on z and apply boundary conditions for yielding:
because of our choice for . Finally, we have:
From (89) and (91), we have that:
Consequently, it remains:
Applying that and are incompressible, we get:
As vanishes on , we integrate this identity by parts leading to:
so that forgetting remainder terms for conciseness:
At this point, we recall the explicit form of :
Consequently, applying (33) there holds:
We recall we have also:
Finally, applying that , we get:
Hence:
so that, introducing and applying Propositions 9 and 12, we obtain as for (85):
Asymptotics of
The computations of follows the line of the preceding section. We first remark that (89) and (90) imply:
so that:
Explicit formulas yield that, for , we have:
Hence, integrating at first w.r.t. z and deleting vanishing terms, we obtain:
As we already computed several times, the vanishing properties of in the origin imply that
and, applying Propositions 9 and 10, we get:
Hence, we have finally: .
Footnotes
Acknowledgements
This paper was written while the first author was visiting the REO Team at INRIA Rocquencourt that he thanks for its hospitality. The first author is supported by the project DYFICOLTI ANR-13-BS01-0003-01.
Proof of Lemma 17
This appendix is devoted to the proof of Lemma 17.
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