We consider fourth order ordinary differential operator with compactly supported coefficients on the line. We define resonances as zeros of the Fredholm determinant which is analytic on a four sheeted Riemann surface. We determine estimates of the number of resonances in complex discs at large radius. We consider resonances of an Euler–Bernoulli operator on the real line with the positive coefficients which are constants outside some finite interval. We show that the Euler–Bernoulli operator has no eigenvalues and resonances iff the positive coefficients are constants on the whole axis.
There are a lot of results about resonances for 1-dim second order operators, see e.g., [11,14,21,35,39] and references therein. We can say that problems of resonances for these operators are well understood. The resonance scattering for third order operators on the line was considered in [27]. There are a lot of papers [5,17,18], …and even a book [6] about scattering for one dimensional higher order operators. Unfortunately, even the inverse scattering problems for higher order operators on the line are not solved and there are only few results about resonances [4,27].
We discuss resonances of fourth order differential operators H with compactly supported coefficients on the line given by
where the operator is unperturbed. Below we assume that our coefficients are real-valued functions and , where , are the spaces of compactly supported functions
for some . Our operator H is self-adjoint on the corresponding form domain (see Section 2). The operator H has purely absolutely continuous spectrum plus a finite number of simple eigenvalues on the real line, see Theorem 1.1.
We define the Fredholm determinant by (1.6), which is analytic on a four sheeted Riemann surface of the function . We define a resonance of the operator H as a zero of the Fredholm determinant on the non-physical sheets of this surface.
Our main goal is to obtain estimates of D and determine asymptotics of the number of resonances in the large disc. Moreover, we derive trace formulas in terms of resonances and prove a Borg type results about resonances for Euler–Bernoulli operator.
Schrödinger operator
In order to discuss resonances for fourth order operators we consider a Schrödinger operator h on given by
where is the unperturbed operator and the compactly supported potential . We recall the well known results for the operator h, see, e.g., [8–10]. The operator h has purely absolutely continuous spectrum plus a finite number of simple eigenvalues . We define the resolvent and the operator for by
Each operator , is trace class and thus we can introduce the Fredholm determinant by
The function is analytic in and has an analytic extension to . It has simple zeros (the eigenvalues) in and there are no other zeros in . Moreover, has an infinite number of zeros (resonances) in . The operator h is self-adjoint and then the set of resonances is symmetric with respect to the imaginary axis, see Fig. 1.
Resonances for the Schrödinger operator h. The resonances are marked by circles. The forbidden domain for the resonances is shaded.
The problems of resonances for 1-dimensional Schrödinger operators with compactly supported potentials are well understood. Recall the following results:
Let and let be the number of zeros of in a disk . Zworski [39] determined the following asymptotics (see also [11,23,35])
For each the number of zeros of with modulus lying outside both of the two sectors is for large r.
There are only finitely many resonances in the domain .
The resonances may have any multiplicity (see [23]).
Inverse resonance problem (uniqueness, characterization and recovering) was solved in terms of resonances for the Schrödinger operator with a compactly supported potential on the real line [23].
Stability estimates for resonances were determined in [22] and [29].
Lieb–Thirring type inequalities for resonances were obtained in [26].
Determinant
In order to define the Fredholm determinant for the operator H we need a factorization of the perturbation V in the form
We introduce a new spectral variable by , where the spectral parameter λ belongs to the cut plane and the sector is given by
see Fig. 2. Introduce the free resolvent and the operator by
In Proposition 1.1 we show that each operator , is trace class. Thus we can define the Fredholm determinant , by
If is a zero of the determinant D, then and λ is an eigenvalue of the operator H. We present preliminary results about the determinant.
The plane of variable k. The function is real on the line . The resonances are marked by circles. The forbidden domain for the resonances is shaded.
Let. Then
Each operator, is trace class and the operator-valued functionis entire in the trace norm.
The Fredholm determinantis analytic inand has an analytic extension tosuch that the functionis entire. In particular, the operator H has a finite number of eigenvalues. Moreover,is real on the lineand satisfies the identitythe estimatesfor all, and the asymptoticsuniformly in.
The function is symmetric with respect to the line . Thus it is sufficiently to analyze this function in the half-plane .
The function is analytic in and may have a pole of order at the point . The zeros of the function D in are called resonances of H. Let be the number of zeros of the function D in the disc , counted with multiplicity. Introduce the domains
Now we formulate our first main result.
Let. Then the determinantsatisfieswhereandthe counting functionsatisfiesMoreover, ifis a resonance, then
The estimate (1.13) gives that the domain is forbidden for resonances in and, due to the symmetry of the function , the domain is forbidden for resonances in , see Fig. 2. The proof repeats arguments from [21].
Estimate (1.10) is crucial to prove trace formula (1.19) in terms of resonances.
In the proof of the estimate (1.12) we use the method from [26].
Due to (1.7) the set of resonances is symmetric with respect to the line (with the same multiplicity).
Consider a specific case when the coefficients satisfy . Then H has the form , where h is the Schrödinger operator, given by (1.2). The determinant D for the operator satisfies the identity
see [3, Prop 3.2], where is the determinant for the operator h, given by (1.3). Thus in this case we can describe resonances of H, see Fig. 3(b). For example, due to Zworski [39], we obtain the asymptotic distribution of resonances. The resonance of the operator h, and then of , may have any multiplicity, see [21]. Moreover, we have the forbidden domains for the resonances of the operator in the quadrants (on the non-physical sheets ) and there are no forbidden domains in (on the non-physical sheet ).
(a) Resonances for the second order operator h; (b) Resonances for the fourth order operator .
We describe the main difference between the case of the second and fourth order operators.
Recall that for Schrödinger operators the Riemann surface in terms of the momentum k is the complex plane. The upper half-plane corresponds to the physical sheet and the lower half-plane corresponds to the non-physical sheet. In order to determine asymptotics of the determinant of the Schrödinger operator in the complex plane it is sufficiently to obtain the asymptotics of the determinant and the scattering matrix in . The Birman–Krein formula (see (2.10)) gives the asymptotics of the determinant in .
In the case of fourth order operators the Riemann surface has 4 sheets and each quadrant of the variable corresponds to the sheet of the Riemann surface . Using arguments similar to the second order case we obtain asymptotics of the determinant in the domains only (and, by the symmetry, in ). In fact, if we have asymptotics of the determinant and asymptotics of the scattering matrix in , then using the identity (4.9) we obtain the asymptotics of the determinant in . In order to obtain the asymptotics in the domain we use additional arguments from [27] (for third order operators), more complicated than for the sectors . We need to introduce an additional matrix-valued function , which satisfies the identity (4.10). Having asymptotics of the determinant and of this matrix in and using the identity (4.10) we obtain the asymptotics of the determinant in . Note that in order to determine asymptotics of determinants for N order operators we need to introduce the corresponding matrix-valued functions.
Asymptotics of resonances
Introduce the Cartwright class of functions. Recall that an entire function is said to be of exponential type if there is a constant A such that everywhere. The infimum of the set of A for which such inequality holds is called the type of f. For each exponential type function f we define the types in by
The function f is said to belong to the Cartwright class if f is entire, of exponential type, and satisfies the following conditions:
for some . We recall the Levinson theorem (see [19]):
Let an entire function f be in the Cartwright class. Letbe the number of zeros of the function f in the disc, counted with multiplicity. Then
Roughly speaking the Fredholm determinants of second order operators on the real line with compactly supported potential belong to the Cartwright class:
Schrödinger operators with compactly supported potentials [39],
Schrödinger operators with periodic plus compactly supported potentials [24],
Schrödinger operators with matrix-valued compactly supported potentials [30],
Dirac operators with matrix-valued compactly supported potentials [16].
In all these cases the Fredholm determinants are entire and belong to the Cartwright class, and the corresponding Riemann surfaces are two sheeted. Thus the Levinson Theorem describes the distribution of resonances in the large disc.
We underline that the Fredholm determinants of the Stark operator with compactly supported potential does not belong to the Cartwright class, since the order of determinants is , see [28]. In this paper we show that the determinant for a fourth order operators does not belong to the Cartwright class also.
We determine asymptotics of resonances for fourth order operators under the stronger conditions for the coefficient p and the standard one for q:
Introduce the model numbers (see Fig. 4) by
where
Asymptotics of resonances for step coefficients.
Letsatisfy the conditions (
1.15
). Then for anythere existssuch that in each disk, there exists exactly one resonanceand there are no other resonances in the domain. These resonances satisfyIn particular, there are finitely many zeros ofon. Moreover, letbe the number of zeros of the function D in a domaincounted with multiplicity. Thenasand the determinant D does not belong to the Cartwright class.
From (1.17) we obtain . It means that the number of resonances in the large disc in the domain is in two times more than in the domain , see Fig. 3.
Our next results are devoted to trace formulas in terms of resonances. Recall that the function may have a pole at the point . Then the function satisfies
for some , where is an order of the pole. Let , be the zeros of the function D in labeled by counting with multiplicities.
Letand let. Then the following trace formulaholds true for all, where the series converges absolutely and uniformly on any compact subset in, andare defined in (
1.18
).
A trace formula for the scattering phase function is proved in Theorem 5.2.
Euler–Bernoulli operators
We discuss resonances of the Euler–Bernoulli operator
acting on . We assume that the coefficients are positive, outside a unit interval and satisfy . The Euler–Bernoulli operator describes the relationship between the thin beam’s deflection and the applied load, a is the rigidity and b is the density of the beam, see, e.g., [38].
In Section 5.3 we show that the operator is unitarily equivalent to an operator with specific coefficients . Then we can define a determinant for the operator as the determinant for the operator H with these . Applying the results for the operator H to the operator we obtain the following corollary of Theorem 1.2.
Letandand letbe positive. Then the determinant, the counting functionand the resonances for the Euler–Bernoulli operatorsatisfy the estimates (
1.10
)–(
1.13
), where
Now we formulate our result about the inverse resonance scattering for the Euler–Bernoulli operator .
Letand letbe positive. Then the operatordoes not have any eigenvalues and resonances iffon the whole line.
Historical review
There are a lot of results about resonances. We recall that resonances, from a physicists point of view, were first studied by Gamov [12]. Since then, properties of resonances have been the object of intense study and we refer to [37] for the mathematical approach in the multi-dimensional case and references given therein. We discuss the one-dimensional case. A lot of papers are devoted to the resonances the one-dimensional Schrödinger operators with compactly supported potentials, see Froese [11], Korotyaev [21], Simon [35], Zworski [39] and references given there. We recall that Zworski [39] obtained the first results about the asymptotic distribution of resonances for the Schrödinger operator with compactly supported potentials on the real line. Inverse problems (characterization, recovering, plus uniqueness) in terms of resonances were solved by Korotyaev for the Schrödinger operator with a compactly supported potential on the real line [23] and the half-line [21], see also Zworski [40] concerning the uniqueness.
There are few papers devoted to systems. Nedelec [30] considered resonances for Schrödinger operators with compactly supported matrix-valued potentials on the real line. Iantchenko and Korotyaev [16] considered the Dirac operator on the real line with 2 × 2 matrix-valued compactly supported potentials. They obtained asymptotics of counting function of resonances, estimates on the resonances and the forbidden domain, a trace formula in terms of resonances. Lieb–Thirring type inequality for resonances of Dirac operators with compactly supported matrix-valued potentials on the real line is obtained in [25]. Resonances for Stark operators on the real line are considered in [28]. Here we underline that for all these cases the corresponding Riemann surfaces are two-sheeted similar to the Schrödinger operator case.
A lot of papers are devoted to the inverse scattering theory for fourth order operators on the line, see papers Aktosun and Papanicolaou [1], Butler [7], Iwasaki [17,18], Hoppe, Laptev and Östensson [15] and the book Beals, Deift, Tomei [6] and references therein.
Resonances for higher order operators with compactly supported coefficients were considered by Korotyaev [27] firstly for the case of third order operators. Here general properties of resonances were described. In particular, upper bounds of the number of resonances in complex discs at large radius and the trace formula in terms of resonances were obtained. Note that this case is very complicated for the consideration since the Born term roughly speaking is constant. Recall that for Schrödinger operators the corresponding Born term is the Fourier transformation of the potential. It is important for the global analysis of resonances, including inverse problems.
Resonances of fourth order operators with compactly supported coefficients on the half-line were studied by Badanin and Korotyaev [4]. Asymptotics of resonances and trace formulas in terms of resonances were determined. This case is simpler, than the case of the line considered in the present paper, because the scattering matrix is a scalar function. An extension of the determinant onto the third quadrant may be obtained using a matrix-valued function Ω. Here the technique from [27] was used. But it is important that the corresponding Born term is expressed in terms of the Fourier transformations of the compactly supported coefficients.
In the present paper the corresponding matrix Ω for an operator on the line is a matrix-valued function and there are some algebraic difficulties in order to obtain this extension. Clearly, the problem for higher order operators will be much more complicated, especially for odd order case.
The usual applications of fourth order differential operators are bending vibrations of thin beams and plates described by the Euler–Bernoulli equation. Many problems of engineering involve solutions of scattering problem for the Euler–Bernoulli equation, see [13] and references therein. Furthermore, the inverse spectral problem methods for some non-linear partial differential equations lead to fourth order operators, see [15].
The plan of the paper is as follows. In Section 2 we study properties of the resolvent of the operator . In Sections 3 and 4 we consider the scattering matrix and the determinant. In Sections 5 we prove Proposition 1.1 and Theorems 1.2, 1.4. Moreover, there we consider the Euler–Bernoulli operator and prove Corollary 1.5 and Theorem 1.6. In Section 6 we obtain asymptotics of the resonances and prove Theorem 1.3.
Properties of the free resolvent
The well-known facts
By we denote the class of bounded operators. Let and be the trace and the Hilbert–Schmidt class equipped with the norm and correspondingly. We recall some well known facts. Let and . Then
see e.g., Section 3, in the book [36]. Let the operator-valued function be analytic for some domain and for any . Then for the function we have
Introduce the space equipped by the norm and we write .
Schrödinger operator
We discuss a Schrödinger operator h on given by
where is the unperturbed operator and the potential .
The operator , is an integral operator having the kernel given by
Define an operator-valued function , where . For each the operator and the mappings
is analytic and it has an analytic extension to . Thus the operator-valued function is analytic. Moreover, we have the following estimate
Define the Fourier transformation by
Then , where is the multiplication by and we have
since .
The Schrödinger equation , has unique Jost solutions satisfying the conditions , and , . For each the function is entire. The following identity holds true:
where the functions a, b are defined by
and denotes the Wronskian. The scattering matrix for the pair h, has the following form
where is the transmission coefficient and are the reflection coefficients. It is well known the following identity for all , where is the determinant defined by (1.3). Moreover, the scattering matrix satisfies
The function satisfies
uniformly on . Then we can define the function by the condition as , which satisfies
The free resolvent
We rewrite the free resolvent in terms of the resolvent by
Then the kernel of the free resolvent has the form , , where
and satisfies
locally uniformly in . Each function , is entire in k.
Define the operator-valued function , , where . The identity (2.11) yields that for each the operator , and the mappings
are analytic and they have analytic extensions to . Moreover, from (2.12) we have the following estimate
Moreover, we obtain , where is the multiplication by , s is the multiplication by and we have
, since .
Resolvent estimates
The operator is self-adjoint on the form domain given by . The quadratic form is defined by , , where is the scalar product in . Then the standard arguments (see e.g., [20]) give
for some constant . Then the KLMN Theorem (see [32, Th X.17]) yields that there exists a unique self-adjoint operator with the form domain and
In order to study the determinant we need to consider . The definitions (1.4), (1.5) imply
We introduce the operator-valued function Y by
This function satisfies the standard identity
where is the set of the zeros of the function D in .
Let. Then
The operator,for each, the operator-valued functionis analytic and has an analytic extension to. The operator-valued functionis entire. Moreover,satisfies
The operatorfor eachand the operator-valued functionis analytic and has a meromorphic extension frominto the whole complex plane. Moreover, Y satisfiesasand uniformly in.
(i) Let . The estimate (2.15) gives
and the estimate (2.7) and the identities (2.11) imply
The identity (2.19) gives (2.22). Substituting the identities (2.11) into (2.19) and using the facts about the mappings in (2.6), (2.14) we deduce that the operator-valued function is analytic and has an analytic extension to . The asymptotics (2.13) shows that the operator-valued function is entire.
Using the estimates (2.9) we obtain for :
and the similar estimates with . These estimates and the relations (2.16), (2.19) give
which yields (2.23).
(ii) For identity (2.21) gives
and, since is analytic in , is analytic in . Due to the analytic Fredholm theorem, see [31, Th VI.14], the function has a meromorphic extension into the whole complex plane. The estimate (2.22) and the identity (2.26) imply (2.24). Moreover,
which yields (2.25). □
The scattering matrix
The spectral representation for
Define a unitary operator
by
The identity , , implies that is the operator of multiplication by in .
Introduce the operator for each by
The definitions (3.1) and (1.4) give
where the operators are given by
These identities yield
where the kernel has the forms:
Introduce the operator , by
The definition (1.4) gives
where the operators have the form
This yields
where
Let. Then the operator-valued functions,, have analytic extensions frominto the whole complex plane and satisfyfor all,,,, where
The identities (3.4) and (3.7) show that the operator-valued functions have analytic extensions from into the whole complex plane. The operator has the kernel given by (3.4). Let . We have
and
This yields the estimates (3.8) for . The proof for is similar. □
Operators ,
Introduce the operators and by
and finite rank operators , acting on , by
The operator-valued functions are analytic in the domain . Below we need the following simple identities.
Let. Then for anythe operatorssatisfy
The identities (2.5), (2.11) yield
For all the identities (3.2) and (3.5) imply
This identity together with the identity (3.13) and the definition (1.5) gives
which yields the identity (3.11).
We define the S-matrix for the operators . It is well known that the wave operators for the pair , given by
exist and are complete, i.e., . The scattering operator is unitary. The operators and commute and thus are simultaneously diagonalizable:
here is the identity in the fiber space and is the scattering matrix (which is a matrix-valued function of in our case) for the pair .
The operator commutes with the operator and the operator is the operator of multiplication by in . Then the operator acts in the space as multiplication by a matrix-valued function .
The scattering matrix is a continuous matrix-valued function in , where is the set of the zeros of the function D in , and satisfies
(see, e.g., [34, Th XI.42]), where is the identity matrix and is the scattering amplitude given by
where the Born term and the term have the form
The operator-valued functions are analytic in , then the matrix-valued function has an analytic extension from into the whole complex plane.
The scattering amplitude
Now we consider the scattering amplitude .
Let. Then the scattering amplitudehas a meromorphic extension frominto the whole complex plane. Moreover, the matrix-valued functionis entire and satisfiesfor all, wherethe matrix-valued functionssatisfyfor all, whereandfor all, where
Let. Then the functionssatisfyas,, uniformly in, where.
(i) The operator-valued functions are entire, then the function has an analytic extension from into the whole complex plane. Due to Lemma 2.1(ii), the function has a meromorphic extension from onto the whole complex plane. Then the scattering amplitude has a meromorphic extension from into the whole complex plane.
The definitions (3.3), (3.6) and (3.17) give
Substituting the identities (3.4) and (3.7) into (3.25) we obtain the identity (3.18), which yields the estimates (3.20). The estimates (2.24) and (3.8) and the identity (3.26) give the estimates (3.21).
(ii) Let . The integration by parts gives
Substituting these asymptotics and the definition (3.19) into the identity (3.18) we obtain (3.22). Similarly,
which yields (3.23).
The definition (3.17) and the estimates (2.25) and (3.8) give
The identities (2.19) and (3.4) imply
Substituting the kernel (2.12) into the last identity and integrating by parts in the first term we obtain
Similarly,
which yields
Substituting this asymptotics into (3.27) we obtain the asymptotics (3.24). □
The determinant
Asymptotics of the determinant
Lemma 2.1(i) shows that , then the determinant is well defined.
Let. Then
The determinantis analytic inand has an analytic extension fromto, such that the functionis entire.
The functionis real on the line.
(i) Due to Lemma 2.1(i) the operator-valued function , and then the determinant , is analytic in and has an analytic extension from to . It is proved in [3, Th 1.2] that the function is entire, the proof is rather technical.
(ii) The identity (2.12) shows that the resolvent kernel , is real on the line , then is real also. Therefore, is real on this line. □
The identities (2.5), (2.11), (2.19) imply
where , . The estimates (2.23) give as . We can define the branch , for and large enough, by
We need the following standard results.
Let. Then the functionsatisfiesfor all,, and for some, where the series converges absolutely and uniformly in k. Furthermore, the functionsatisfies the asymptoticsuniformly in.
Let . The identity (4.1) and the estimate (2.22) give
Then the series (4.2) converges absolutely and uniformly and it is well-known that the sum is equal to (see [33, Lm XIII.17.6]). Using the estimates (4.5) we obtain
for all . This yields (4.3). The estimates (4.3) together with the identity (4.1) give the asymptotics (4.4). □
Identities for the determinant and S-matrix
Asymptotics of the determinant in in the case of the Schrödinger operator is obtained from the asymptotics in and the identity (2.10). In order to determine asymptotics of the determinant in for the case of fourth order operators we need some additional identities. The situation for third order operators is described in [27].
Recall that the S-matrix is a meromorphic matrix-valued function and satisfies the identity , see (3.15), (3.16), where is the Born approximation for the scattering amplitude , .
Introduce the matrix-valued function by
where the “Born” term has the form
are given by (3.9), and
The function has an analytic extension and the functions have meromorphic extensions from onto the whole complex plane.
Let, and let. Then the determinant D satisfiesThe functionis continuous in.
The identities (3.10), (3.11) and (2.21) give
The definitions (3.15), (3.16) give
The identity (2.2) implies (4.9).
Similarly, the identities (3.10), (3.12) and (2.21) give
Then the identity (2.2) and the definition (4.6) imply (4.10).
Due to Lemma 3.3, the function is continuous in and it has a meromorphic extension from onto . Moreover, if , then k is a zero of the functions and of the same multiplicity. Due to the identity (4.9), is continuous at the point . Therefore, is continuous in . □
Asymptotics of Ω
We consider the matrix-valued function . Substituting the definitions (3.9) into (4.7), (4.8) we obtain
Introduce entire matrix-valued functions
The identities (4.11) and the definitions (3.17) (4.12) give
Introduce the domain
Let. Then the functions, given by (
4.12
), satisfywhereMoreover, the functionsatisfiesas.
Substituting the definitions (3.3), (3.6), (3.4) and (3.7) into (4.12) we obtain the identities (4.15).
Let . The definitions (4.16) give
These estimates and the identities (4.15) give
where
These estimates and the estimates (3.20) together with the identity (4.13) give
where
Let . The estimates (3.8) and (2.24) give
where
Substituting these estimates and the estimates (3.21) into the identity (4.14) we obtain
where
Let . Substituting the estimates (4.18), (4.20) into the definition (4.6) we obtain the estimate
for all . Then the definitions (4.19), (4.21) give
where
which yields (4.17). □
(ii) Due to Lemma 4.1, the function has an analytic extension from onto , it is real on the line and the function is entire. The asymptotics (4.4) yields the asymptotics (1.9). This asymptotics shows that the function has a finite number of zeros in . Then the operator H has a finite number of eigenvalues.
We prove the relations (1.8). The first estimate in (4.3) gives
for all , , which yields the first estimate in (1.8). Let , . Then , , , and
This estimate and the second estimate in (4.3) give
for all , which yields the second estimate in (1.8). □
We determine asymptotics of the determinant in the complex plane. Due to the symmetry of we need to get this asymptotics in the domains . The asymptotics in the domain is known due to (4.4). We analyze the function in the domains by the following way. We obtain the asymptotics of and in . Then we use the identities (4.9), (4.10) in order to determine the asymptotics of in , which gives the asymptotics of in .
Let. Thenas,as.
Let . The identity (3.15) and the estimates (3.20) and (3.21) give
where
The estimates (5.6) give
which yields the relations (5.2). The second estimate in (1.8) gives
The identities (4.9) and (5.2) give
The estimates (5.2) and (5.7) give
which yields the relations (5.4).
Moreover, the estimates (5.6) imply
which gives (5.1). The first estimate in (1.8) and the identity (4.9) imply the estimate (5.3).
The estimates (1.8), (4.17) and the identity (4.10) give the estimate (5.5). □
The first estimate in (1.8) gives the estimate (1.10) in , the relations (5.4) and the symmetry give (1.10) in and , the estimate (5.5) and the symmetry give (1.10) in .
The asymptotics (5.4) yields for all . Let be a resonance. Then the identity gives the estimate (1.13).
We prove the estimate (1.12). Recall that the function is analytic in and may have a pole of order at the point . Then the function is entire and satisfies . Let be the number of zeros of the function F in the disc counted with multiplicity. If , then , if is a pole of D of multiplicity m, then .
Let . The estimate (1.8) provides , which yields
Then
The number of zeros of the function F in the disc (the larger disc) and the number of zeros of the function F in the disc (the smaller disc) satisfy .
Let , , be the number of zeros of the function F in the disc counted with multiplicity, see Fig. 5. Recall the Jensen formula (see [19, p. 2]):
Let . Let . Then
Note that
Then the estimate (1.10) gives
where we used the estimates
and , see (1.11). Moreover,
and using , see (5.10), we obtain
Substituting these relations into (5.11) we obtain
Substituting the estimates (5.12) and (5.8) into (5.9) we obtain
where we used the estimate . Moreover,
Thus, we have
The estimate (5.13) together with , see Fig. 5, gives
, which yields
The estimates
give
for all . Substituting and using the estimates
we obtain (1.12). □
Trace formulas
Let , be the zeros of the function D in labeled by counting with multiplicities. The estimate (1.10) provides the standard Hadamard factorization
absolutely and uniformly on any compact subset in , where are defined in (1.18). The identity (5.14) gives
The following proofs use the approach from [21].
Let . The definitions (1.4), (2.12) show that the operators and are Hilbert–Schmidt. Then the operator
is trace class. Due to the identities (2.2), (2.4), (2.21) and , the derivative of D satisfies
The identity (5.15) together with (5.16) yields the trace formula (1.19). □
The S-matrix , is a complex matrix and . Thus we have
Since is continuous in and as (see (5.2)), formula (5.17) determines by the identity , the continuity, and the asymptotics as .
Let. Thenthe series converges absolutely and uniformly on any compact subset in.
The function is continuous in , has a meromorphic extension onto the whole complex plane and, due to equations (5.17) and (4.9), it satisfies the identities
Differentiating this identity we obtain
Then the identity (5.15) implies (5.18). □
The Euler–Bernoulli operator
We consider the Euler–Bernoulli operator
acting on , where the coefficients satisfy
Now we consider the Liouville type transformation of the operator into the operator H, defined by (1.1) with specific depending on . In order to define this transformation we introduce the new variable by
Let be the inverse function for . Introduce the unitary transformation by
Introduce the functions , by
Then the functions are real, compactly supported and satisfy
Let the operator H be defined by (1.1), where the coefficients , have the forms
and the functions are given by
The coefficients satisfy: with γ given by (1.21).
Let the coefficients satisfy the conditions (5.20). Let the operator be defined by (5.19) and let the operator H be defined by (1.1), where the coefficients have the forms (5.24), (5.25). Repeating the arguments from [2] we obtain that the operators and H are unitarily equivalent and satisfy:
where the operator U is defined by (5.22).
Letand letbe positive. Then the determinantsatisfiesuniformly in, whereis given by the definition (
5.26
).
Identity (5.24) gives
Substituting this identities into the asymptotics (1.9) we obtain the asymptotics (5.28). □
The definition (5.26) shows that , moreover, iff . Then the second term in the asymptotics (5.28) vanishes iff . The proof of Theorem 1.6 is based on this observation.
Assume that the operator does not have any eigenvalues and resonances. Then and the second term in the asymptotics (5.28) vanishes. The estimates (5.26) show that in this case, then on .
Conversely, assume that on . Then and the definitions (5.24), (5.25) imply . The identities (1.4) yield . Then the definition (1.5) gives , and the identity (1.6) implies . Therefore, there are not any eigenvalues and resonances. □
Asymptotics of the resonances
Asymptotics of the determinant
The function has a finite number of zeros in the domain . The identity (4.9) shows that with large is a resonance in iff k is a zero of the function in . Thus in order to determine asymptotics of resonances in we need to improve asymptotics of in . Similarly, the identity (4.10) shows that with large is a resonance in iff k is a zero of the function in . Then in order to determine asymptotics of resonances in we have to improve asymptotics of the function in . Moreover, due to the symmetry of the determinant it is sufficient to consider in this case the domain , where
Letsatisfy the conditions (
1.15
). Then the S-matrixand the matrix-valued function, defined by (
4.6
), satisfyas, uniformly in,as, uniformly in.
Let . The definition (3.15) and the asymptotics (3.22) and (3.24) give
where
The asymptotics (6.5) implies
The identity (6.3) and the definitions (6.4) yield the asymptotics (6.1).
We prove the asymptotics (6.2). Substituting the identities (4.13), (4.14) into the definition (4.6) and using the definition (3.15) we obtain
Let , and let . Integrations by parts in the definitions (4.16) give
Substituting these asymptotics into the identities (4.15) we obtain
Repeating the arguments from the proof of the asymptotics (3.24) we obtain
The asymptotics (3.23) and (6.9) give
where
The asymptotics (6.7) and (6.10) imply
where
The asymptotics (6.8) and (6.11) yield
where
Substituting the identities (6.3), (6.12), (6.15) and (6.17) into the relation (6.6) we obtain the identity
The definitions (6.4), (6.13) and the identity (6.19) yield
The standard matrix formula gives
where
Substituting this identity into (6.20) we obtain
The definition (6.14) implies
The asymptotics (6.5), (6.16), (6.18) and (6.22) yield
which yields
Substituting the asymptotics (6.22) and (6.23) into the identity (6.21) we obtain the asymptotics (6.2). □
Asymptotics of resonances
We are ready to determine asymptotics of resonances.
Let and let be a resonance. The identity (4.9) shows that k is a zero of the function in . The asymptotics (6.1) and the identity imply that k satisfies the equation
Then k lies on the logarithmic curve Γ in , given by
and satisfies
and there are not any other large resonances in .
Let , let be a resonance and let be large enough. The identity (4.10) shows that is a zero of the function in . The identity and the asymptotics (6.2) gives
Then k lies on the curve Γ and satisfies
and there are not any other large resonances in . The asymptotics (6.24), (6.25) give the asymptotics (1.16), which yields the asymptotics (1.17).
The estimates (1.10) and (1.18) yield that the determinants is of exponential type. But the asymptotics (1.16) and the asymptotics of the Levinson Theorem (1.14) show that the determinants is not of the Cartwright class. □
Further discussions
We will discuss what properties of resonances of the second and fourth order operators with compactly supported coefficients are common and which are specific.
Common properties:
The determinants and are exponentially type functions of the variable k and each of them has an axis of symmetry.
For coefficients with steps the resonances have the logarithmic type asymptotics.
Specific properties of the determinant for a Schrödinger operator:
In terms of the spectral parameter λ the Riemann surface for the determinant is the two sheeted Riemann surface for the function . The function as on the physical sheet and on the non-physical sheet. It has a finite number of zeros (eigenvalues) on the physical sheet and an infinite number of zeros (resonances) on the non-physical one.
The determinant belongs to the Cartwright class . Then the Levinson Theorem gives the distribution of resonances in the large disc.
The number of resonances in the disk for large r has asymptotics .
Using one identity (2.10) we obtain an analytic extension of the determinant from the physical sheet onto the non-physical one.
Specific properties of the determinant for a fourth order operator:
The Riemann surface for the determinant is the four sheeted Riemann surface for the function . The function D satisfies: at on the first sheet, on the second and fourth sheets and on the third sheet. It has a finite number of zeros (eigenvalues) on the first (physical) sheet and an infinite number of zeros (resonances) on the other (non-physical) sheets. The number of resonances in the large disc on the third sheet is, roughly speaking, in two times more than on the second (or fourth) sheet.
The determinant D is not in the Cartwright class.
The number of resonances in the disk for step coefficients has asymptotics as .
In order to obtain an analytic extension of the determinant from the first sheet onto the other sheets we need to use two identities (4.9), (4.10).
Footnotes
Acknowledgements
A. Badanin was supported by the RFBR grant No. 19-01-00094. E. Korotyaev was supported by the RSF grant No. 18-11-00032. We thank the referee for useful remarks that improves the presentation.
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