A uniformly valid model for the limiting behaviour of voltage potentials in the presence of thin inhomogeneities II. A local energy approximation result
Available accessResearch articleFirst published online March 27, 2020
A uniformly valid model for the limiting behaviour of voltage potentials in the presence of thin inhomogeneities II. A local energy approximation result
In this second part of a two part paper, we establish a local, uniform
energy-approximation estimate for the solutions to a simplified model of thin
inhomogeneities with open mid-curves. This local result plays a crucial role in the proof
of the global, uniform approximation results established in the first part of this paper
(Asymptotic Analysis (2019)).
For more details about the model we also refer the reader to (Chinese Annals of
Mathematics, Series B38 (2017) 293–344).
Let σ denote the line segment and let
denote the
symmetric domain
For any ,
and arbitrary constants , we introduce the
following two energy expressions
Here
and
Note that these are exactly the energy expressions introduced in the first part of this
paper, with the proviso that f vanishes in ; they are defined on
and , respectively. This second
part of the paper is entirely devoted to the proof of the following local, uniform energy
convergence result.
Letanddenote the minimizers of the energies (
1
) and (
2
), respectively, given Dirichlet boundary data. Thenas.
Due to the symmetric nature of , we may decompose the solutions,
and
,
into their even and odd parts with
and similarly for
,
. A simple
calculation yields that for any
, , and for any
. If we combine this with the
fact that then Theorem 1 follows as an immediate consequence of the following two
lemmata.
as.
as.
The proofs of Lemma 1 and Lemma 2 (which complete the proof of Theorem 1) are the
focus of the remainder of this paper. The proofs proceed in five steps. In Sections 2–3 we establish estimates for
separately, when
(Section 2), and when (Section 3). In Sections 4–5 we establish estimates for separately, when
(Section 4), and when
(Section 5). In Section 6 we combine the
estimates from the previous four sections to obtain proofs of Lemma 1 and Lemma 2.
Local convergence – Even symmetry,
In this section we shall show that, in the regime ,
for any . The essential fact is
that the constant depends on the lower
bound m, but is otherwise independent of
and
ϵ. Here and
are the energy
expressions introduced in (1) and (2). When restricted to even functions, these are given by and
and
are the respective
minimizers with Dirichlet boundary data . The proof of
(3) is fairly involved and proceeds in two stages; in the
first stage we verify that and in the
second stage we verify that for any
. To accomplish the second
stage, we introduce a dual energy principle. The idea of using a combination of primal and
dual variational principles to obtain bounds on absolute energy differences has a long
history in the theoretical mechanics literature, we refer the reader to [4] for an early example.
Let K be a fixed compact set inside , which contains σ in
its interior. Since our analysis and estimates are asymptotic in , we shall
without loss of generality throughout this paper assume that ϵ is
sufficiently small that . In the remainder of this
section we shall for simplicity of notation drop the subscripts m and
γ from the constant . For simplicity of
notation we shall also delete the explicit appearance of in the energy symbols, in other
words we shall use and
in place of
and
.
For any ,
let denote the nearest point to
on σ. We may define a natural
map by
This map Φ also maps
1-to-1 onto . For an arbitrary
, define
by , then a simple calculation gives
Here denotes the square
and
denotes the
complement of ,
i.e., . Let
denote the vector
space
Let denote the energy
The earlier calculation shows that and as a
consequence, for
any pair of functions , with
on
. We now
construct an element in that makes the right
hand side of (8) of the order .
For that purpose let us try ,
but
is not quite in
, since it fails to
satisfy the condition on
.
To remedy this, we introduce as the unique solution to
In Appendix A it is shown that
By construction, the pair belongs to
and
on
. Inserting the
pair as a “test function” in
, and using
Lemma 3, we now calculate: and so by
insertion into (8) we obtain as desired.
We note that has singularities of
the form near the endpoints of
σ (see Proposition 1 of [1]), and that
Since this appears to be of the same order as (see
Proposition 1 of [1]) one might expect that
the singularities would contribute to the “limiting energy” . The analysis in
this section has shown that, if instead of accounting for the boundary discrepancy in
by adding a corrector inside , one adds a
corrector outside
, one may indeed
do so in a way that is of the order ,
and thus doesn’t contribute to the “limiting energy”.
It is well known that
where the complementary energy expression is given by
We may split the volume integral as
Consistent with this splitting, the maximization in (10)
may be rewritten as taking place over
From now on n denotes the outward normal to at
(or to
at ).
Let denote the
previously defined 1-to-1 mapping of
onto . As
ranges over the set for a
fixed ,
then the vector field ranges over the
set and
From these calculations it follows that
where is given by
and the set is given by
We now divide
into two parts as before
and compute and
It thus follows that and that
alternatively may
be characterized as
From (11) we have that for
any pair . We now proceed to
construct a test pair from , so that we may
establish (7), in other words a test pair which satisfies
From the representation formula for in Proposition 1 of
Appendix A in [1], and the remark immediately
following that proposition, we know that where
and are polar coordinates around the two endpoints
of σ, and
is bounded in , up to the curve σ, by
.
Here we make use of the fact that . If we differentiate
this representation with respect to y and evaluate it on
σ, then we obtain for
. Notice that these two
functions are not in . However, we may define
approximations that are in ,
as follows with
the constant chosen so that
This requires that
Since , we observe that
. We also calculate
Define the function R by
A simple calculation shows that
The function R is actually continuous with the same
-bound
of , and
To construct a test pair for (16) we select
and define
by and,
The pair clearly lies in ,
and it satisfies the two divergence constraints prescribed in :
Here we use the fact that in
. We also use (20) and the fact that which follows
from the decomposition (17) and Lemma 2 in Appendix A of
[1]. In general, this pair
fails to satisfy the “interface” conditions,
instead it satisfies and
To remedy this situation we seek
so that
In Appendix B it is shown that
It is possible to find a field, which satisfies the requirements (
22
), together with the estimatefor any.
Given such a , the pair
is in . We now calculate
From a standard energy estimate we have and by insertion
of this and the estimates (18), (19) and (23) into (24), we arrive at since by
assumption is bounded uniformly
away from zero. The exponent γ may be chosen arbitrarily close to 1.
Insertion of this inequality into (16) now finally yields
which completes
the proof of (7).
Local convergence – Even symmetry,
In this section we shall show that, in the regime , for any
. Here
and
are the energy
expressions introduced in (1) and (2), which when restricted to even functions are given by (4) and (5). We shall prove (25) in two steps: first we prove and
then we prove
Here denotes the solution to
which is
obtained through the minimization with
The estimate (25) follows immediately by combination of (26) and (27). For simplicity of
notation we shall in the following delete the explicit appearance of
in the energy
expression symbols, in other words we shall use ,
, and
in place of ,
and
.
We also drop the subscript γ on the constant .
Due to the minimizing properties of and
, and the
positivity of ,
Here we have used that is indeed in
(not just in
) due to its even symmetry.
We have also used that, due to elliptic regularity,
The previous set of inequalities yields that which immediately
leads to the estimate (26).
In this subsection we shall prove that
We achieve this in two steps, by proving that and
for any
. We calculate
to establish
(28). By duality we know that where
denotes the following set of vector fields
As a test field, we define
where is selected so
that and
To construct , we use a simplified
version of the approach we use in Appendix B to prove
Lemma 4. We first construct a function V
on by counterclockwise
integration of along :
on
(with
s denoting arclength, and
corresponding to the point ). We then
extend V to by setting it to
be constant along normal rays emanating from . Since
is
strictly inside (with
-norm
bounded by ),
and since
on , this
extension, V, is in , with
for any
. We cut V
off near the boundary, so that near
, and then
define
This field satisfies
Furthermore satisfies (31) and (32), and so
defined by
(30) lies in the set W. We now calculate
which establishes
(29).
Local convergence – Odd symmetry,
We now move to consider the case of odd symmetry. When restricted to functions with
, , the energy
, given by (1), takes the form where
denotes the domain . The minimizer of the energy
in
is thus entirely determined by
We introduce the auxiliary problem and let
denote the associated
energy defined on
. The function
is simply the
restriction to
of the minimizer of this energy in ; we denote the minimizer
(defined on all of ) by
as well. Note that
is exactly the
solution, for which we studied the regularity in Appendix B of [1]. The important role played by is due to the following
lemma.
Under the assumption that, for some fixed constant M, the following estimate holdsuniformly inand.
In order to prove this lemma we shall use the previously noted fact that
as well as the fact that
We shall rely on the decomposition of (in
)
established by Proposition 2 in Appendix B of [1], namely where
and denote polar coordinates around the two
endpoints of σ and the remainder
is in for any . Furthermore
uniformly in
ϵ and (since
). K is a compact subset of
, which
contains σ in its interior. We notice that, due to the minimizing
properties of and
(on
),
and the positivity of ,
It follows from (34) and (35)
that
We now define the following (smoother) approximation to (on
)
where
,
and
are as above, and δ is a fixed positive number. Notice that
lie in (in contrast to
,
which do not). Also notice that is odd in
y and at
.
With this definition it can be verified that
and
Due to (34) and the minimizing property of
, we therefore
calculate
In the second to last estimate we also used that . Due to (34) and
(35) it follows from above that
A combination of (36) and (37)
completes the proof of Lemma 5. □
We shall now relate to a problem with even
symmetry through duality. For that purpose consider the field , which is in
and has divergence 0 in .
Therefore, there exists , with satisfying
the additional constraint . It
follows that for any
function . Here we note that, according
to the earlier representation formula for ,
(and thus
) is in
, for any . Due to the boundary
condition of on σ
we calculate for any
. To obtain the last identity
we used that vanishes at the
endpoints of σ, which follows from the fact that it is continuous on
, and vanishes outside σ
(because of the odd symmetry). Also note that the last integral makes sense, because
is in
, due to the earlier
representation formula, and because z is in . Due to the relationship
between and
, and to the fact that
vanishes on
outside σ,
for any
. A combination of (39), (40), and (41) yields for all
. It follows that
is the solution to
with
. Here
n denotes the outer normal to
and τ is the counterclockwise tangent. Let
denote , which is well
defined (and an even distribution) on all of , and let denote the (variational)
solution to with the
additional constraint .
is the even extension of to all of
, and is a
minimizer of the energy in the set
. Furthermore
We calculate
Since on σ,
we also have and due to
(38)
Upon insertion of these last three identities into (43), we
get
Let denote the solution
to the problem with
the constraint . Here the
coefficient is given by
is a minimimizer of
the energy in the space
. is related to
, the minimizer of
in
, by furthermore
The analysis in Section 2 was performed with Dirichlet boundary
conditions on , but it could as well have been
performed with Neumann boundary conditions, and with in place of
. It would then apply
to the case , which (with
) is exactly the case we are dealing with here. The equivalent of (3) would now estimate the energy difference between
,
the solution to (42), and , the solution to
(45) – it asserts that
If we substitute (44) and (46)
into this, we arrive at the estimate
A combination of this estimate with the estimate in Lemma 5
establishes
Under the
assumption that, for some
fixed constant M, the following estimate holdsuniformly inand,
for any.
Local convergence – Odd symmetry,
In this section, we shall prove that in the regime ,
We prove this estimate in two steps: first we prove and then
we prove
Here denotes the solution to
which is
obtained through the minimization with
The estimate (48) follows immediately by combination of (49) and (50). For simplicity of
notation we shall in the following delete the explicit appearance of
in the energy
expression symbols, in other words we shall use ,
, and
in place of ,
and
.
We shall use also to denote the
restriction of to
.
This restriction solves the boundary value problem (33),
and is the minimizer of the energy in the set
Furthermore . We now calculate
in other
words
In order to prove a corresponding lower bound we apply
a dual variational principle for (on
).
It is fairly simple to verify that
where the set W is defined by
The equations in the definition of W are to be interpreted in the sense
of distributions, by which we mean for any
smooth function ψ on ,
which vanishes on
and on . Based on (53),
and taking , we calculate thereby
establishing (52). A combination of (51) and (52) immediately leads
to (49).
Given , the minimizer of
, we first construct an
approximate minimimizer for the energy . We define
where lies in
with and
for any
. In order to construct this
, we note that
the “ends” of
, and
the horizontal
parts of . We then construct
by extending
from
to
constantly along
normal rays, and we apply a cut-off to near
. With this
construction it is fairly easy to check (based on the observations about
above) that (54) holds. Using we calculate
This verifies that
We proceed to verify the corresponding lower bound
For that purpose, we use the dual variational formulation for and select the
test field (which satisfies
in ) to get
A rearrangement of this estimate immediately gives the lower bound (56), and a combination of (55)
and (56) now leads to the desired estimate (50).
In this section we combine the estimates from the previous four sections to obtain proofs
of Lemma 1 and Lemma 2. We start
with
Suppose the statement in Lemma 1 was not true. Then there
would exist sequences and
, and a constant
, such that
There are two possibilities concerning the sequences and
:
There exists a constant
so that
.
There exists a subsequence of the (for
simplicity also called ) so that
.
In case (1), we have from Section 2 that
This clearly represents a contradiction to (57).
In case (2), we have from Section 3 that
However, this is clearly also a contradiction to (57), as
.
In summary we have established a contradiction to (57) in
both cases (1) and (2), and so we conclude that the statement of Lemma 1 is indeed true. □
Suppose the statement in Lemma 2 was not true. Then there
would exist sequences and
, and a constant
such
There are two possibilities concerning the sequences and
:
There exists a constant
M so that .
There exists a subsequence of the (for
simplicity also called ) so that
.
In case (1′), we have from Section 4, Lemma 6, that
This clearly represents a contradiction to (58).
In case (2′), we have from Section 5 that
However, this is clearly also a contradiction to (58) as
.
In summary we have established a contradiction to (58) in
both cases (1′) and (2′), and so we conclude that the statement of Lemma 2 is indeed true. □
Footnotes
Acknowledgements
This work was partially supported by NSF grant DMS-12-11330. Additionally MV was supported
by the NSF IR/D program while serving at the National Science Foundation. Any opinion,
findings, and conclusions or recommendations expressed in this paper are those of the
authors, and do not necessarily reflect the views of the National Science Foundation.
Proof of Lemma 3
From the representation formula for in Proposition 1 of
Appendix A in [1], and the remark immediately
following that proposition, we get that where
and are polar coordinates around the two endpoints
of σ, and
is bounded in , up to the curve σ, by
;
similarly
and
are bounded by .
Here we make use of the fact that Lemma 3 only concerns the
case . We decompose
, the solution to
(9), as follows where
is the solution to
and is the solution to
Notice that .
First, we estimate . For that purpose, we
divide into two parts
and
On it follows
immediately from the fact that
is (up
to σ, but not across σ) that
On the function
is identically
equal to (on the left component of
) or
(on the right component of
) and
is identically equal to 0.
From Lemma 2 in Appendix A of [1] we have that
, and from
the even symmetry of
we also have that ; in summary
Since
is (up
to σ) it now immediately follows that and
Together these yield
By a combination of (62) and (64) it follows that
The function is indeed
on , but we don’t use that
fact here. By a simple construction, we may extend the trace to
a function defined on the whole
domain with
on and
One such extension can be obtained by extending constantly on normal rays emanating from
, and then
multiplying by a smooth cut-off function to get value zero at . The standard
variational formulation of (61) asserts that
in other words, and so
which is
the desired estimate for . It remains to estimate
the function , defined by (60). To that end we define an extension of
to
a function , defined on the whole
domain , with
on and
We start by defining in
, the region denoted
A in Fig. 1. On the part of
which lies inside
,
is
given by . We now define
where
is a smooth
cut-off function (with for
and for
)
which ensures that vanishes on
. It is clear
from this definition that
We now continue to define on
, the region denoted
in Fig. 1, such that and
most importantly
In order to verify the existence of this
extension it suffices to prove that the prescribed set of boundary values (67) are bounded by in the
norm. It is clear that
Concerning , we calculate
on , from which we conclude that
and so by
logarithmic convexity of the norms
Finally, consider the integral
By combining (68), (69)
and (70) with the fact that vanishes on
and on
, we now conclude that the
prescribed values of on the boundary of
(the region denoted
B in Fig. 1) are bounded by
in the
norm.1
Here we use the well known fact that a function
v, which lies in and in
and for which
is finite, indeed lies in
on the entire interval . The sum of the
norm, the
norm and square root of
this integral is equivalent to the norm, [3]. It is not essential that the two segments
meet at an angle of π, they could form a corner, and the same norm
characterization would still be valid.
It follows immediately that we may
extend to all of
, with
The domain does depend on
ϵ, but the fact that it is uniformly diffeomorphic to a fixed
domain ensures that the constant C is independent of
ϵ.
A similar construction works for
, so that
altogether we have constructed with the desired
boundary values and with
By joining together the two constructions of in the disjoint regions
and
, we obtain (due to the continuity across the
line )
a function in all of
which satisfies together
with the estimate
This last estimate is obtained by a combination of (66) and
(71). An entirely similar construction works on the
domain , and by merging these two constructions (using
the fact that both constructions vanish on ) we have
constructed the desired function, , with
We may now use this function , the same way we used
the function , to show that
, defined by (60), satisfies or
for any
. Due to (65) and (73) we now get that the
corrector function , defined by (9), satisfies for any
, as asserted in Lemma 3.
Proof of Lemma 4
We notice that Lemma 4 only concerns the case
. A simple computation
shows that
Here we use the fact that
in . Since
it
immediately follows that the assigned values for
from (22) satisfy
Given these assigned values for , we define where
s denotes (counterclockwise) arclength along , and the integral
is taken along , from arclength 0 to
arclength s. We define arclength 0 to correspond to the point
on (the point between
components A and B in Fig. 2). The representation formula in Proposition 1 of Appendix A in [1] implies that on
. Due to the
nature of ,
and the fact that (see (63) of Appendix A in this paper),
we have that
By counterclockwise integration the function V has the representation
in polar coordinates on . By extending
V as a constant function along straight rays emanating from
,
i.e., by defining we obtain (as
in the case of and
) an
function V on (the component
A in Fig. 2), which vanishes on
, and satisfies
for any
. On
(the lower
boundary of the component B in Fig. 2) the
function V has the formula
Let denote the
function
A change of variable yields
We have that and
It immediately follow that with
Since , it follows that
and since
is in
we have that for
. By
combination of these last three estimates with the representation (75) we conclude that
On , the first
derivative of has the
representation
We calculate, with
Due to the bound on and the nature of ,
we also have
A combination of (78), (79), and (80) now gives so that, due to
(77), we may conclude
This estimate in combination with (77) and the logarithmic
convexity of the Sobolev norms yields for any
. We also calculate the
integral
By application of Hölder’s inequality to the formula (76)
for g we get for any
and
. Based on this estimate we obtain
for any
. We also have
and so
which gives
Insertion of (83) and (84)
into (82) leads to the estimate for any
. In light of the estimates
(81) and (85), we conclude
that the boundary data, consisting of the function 0 on and the
function on , is in with a
norm bounded by ,
and thus this combined datum permits an
extension V to the region in Fig. 2, with
The same construction works on , the region
denoted
in Fig. 2, given constant boundary data
on and boundary data , on
(note that arclength = corresponds to the point
on ). By combining the
(three) constructions carried out so far, we obtain an
function V on , with
A similar construction for would lead to a function
, with
On the “interior” segments of it is clear that the
function has -norms
bounded by
(actually its -norms
will be bounded by )
and so we may also easily construct an
function V on with
By pasting these constructs for ,
, and
together using a partition
of unity (in x) we finally obtain a function with
By multiplication with a smooth cutoff function (vanishing near and equal to 1
in a fixed, ϵ independent subdomain containing ) we may assume that
V vanishes in a neighborhood of . Having constructed this
extension V in all of , we now define
This is a solution to
(22) (since
assumes the required boundary data on and
), with
as asserted in
Lemma 4.
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Uniform asymptotic expansion of the voltage potential in the presence of
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