The goal of this paper is to explore the asymptotic behaviour of anisotropic problems governed by operators of the pseudo p-Laplacian type when the size of the domain goes to infinity in different directions.
When Ω is a bounded open set of , we denote by , , the usual Sobolev space constructed on , of functions vanishing on the boundary of Ω. That is to say we set
We equip this space with the norm
and we set
( denotes the space of -functions with compact support in Ω). It is well known that is a reflexive Banach space which can be equipped with the equivalent norm
(∇ denotes the usual gradient an the euclidean norm, i.e. , denotes the -norm on Ω). The dual of is denoted by , and consists in the distributions of the form
We use the notation
The paper is organised as follows. In the next section we address the case of a simple problem set on a rectangle with one side going to infinity. We consider all the possible values of , for the pseudo -operator at hand allowing to present a variety of techniques. Some of them are issued of previous works. We refer the reader to [3,5,10,11,15], for details. The Section 3 relies on the experience acquired on the simple model investigated in Section 1 to extend some results to more complex situations. The operators at hand are Euler equations of some anisotropic functionals of calculus of variations introduced for other reasons in [17], see also [18]. For basic notions on Sobolev spaces we refer to [1,12–14,16].
A model problem
We denote by the open subset of defined as
We will set and will denote the boundary of , see the Fig. 1 below.
The domain .
If are two positive numbers we would like to consider solution to
More precisely we are interested to the asymptotic behaviour of when . f is a function or distribution depending only on . A natural candidate for the limit of the problem is solution to
where is the boundary of ω. First let us recast these problems under their natural weak form.
We can first introduce the weak formulation of (2.3). If is given by
where then, the weak formulation to (2.3) corresponding to f reads
To arrive to a weak formulation for (2.2) one introduces
It is a reflexive Banach space when equipped with the norm
Then we define
If f is defined by (2.4) if follows easily that there exists a unique weak solution to (2.2) i.e. satisfying
We are interested in showing that when , but also to investigate at what speed. We will now denote by .
The operators defined by (2.2), (2.3) are strictly monotone, hemicontinuous, coercive from , into their duals. Existence and uniqueness of a solution for (2.9), (2.5) follows from classical arguments (see [4,12,16]).
Let us first prove the following lemma.
Suppose that f is given by (
2.4
). Ifis the solution to (
2.9
) there exists a constant C independent of ℓ such that
Taking in (2.9) we get
this by the Hölder and the Poincaré inequality. Let us recall regarding this last point an argument that we will use several times later on. If , let such that in . By the Poincaré inequality on ω one has for some constant C independent of ℓ
Integrating in we deduce
and passing to the limit in n the same inequality holds for u or . Then let us notice that for one has
Thus from (2.11) we derive for some constant
Since this is equivalent for some new constant to
Going back to (2.11), the result follows. □
Somehow one can ignore f thanks to the following remark.
Ifis the solution to (
2.9
) andsolution to (
2.5
) one has
First by (2.9) if one has
If one has for almost every
Thus by (2.5)
Integrating in it comes
Subtracting from (2.13), (2.12) follows. □
Let us recall the following result (see [4,6]) which garanties also the strict monotonicity of the operators at hand.
For anythere exist positive constants,such that
Then one has:
Letbe the solution to (
2.9
) andbe the solution to (
2.5
). Suppose that,then one has(If f is not a function,means,).
We use the notation . From (2.9) by subtraction we get
Taking one deduces easily using the lemma 2.3 that i.e. (see below (2.18) for a similar argument).
If taking , one gets .
Regarding , taking in (2.5) one gets for
This reads also
Thus and . Then taking in (2.12) one gets
i.e.
This implies that the set is of measure 0 since on this set i.e. (see [14]). This completes the proof of the Lemma. □
Let us now show:
Ifis the solution to (
2.9
) andsolution to (
2.5
) one has for every smooth functionvanishing at
Taking in (2.12) one gets
(Recall that is independent of ). Then (2.19) follows easily. □
Denote by a smooth function such that
and set
where . We can now prove:
Letand,be the solutions to (
2.9
), (
2.5
). Then it holds for some constant C independent of ℓ
From (2.19) one derives
Noting that and using Hölder’s inequality it comes
Thus it follows that
provided we chose . From the lemma 2.4 one has
(notice that ). Then one derives
Since this last function is independent of one derives from (2.25)
for some new constant C. This is (2.22). This completes the proof of the lemma. □
We give now a very simple proof of the convergence of toward which is valid for every p and q.
Letand,be the solutions to (
2.9
), (
2.5
). Then for anyit holds when
The first part of (2.26) follows immediately from (2.22) if one chooses . For the second part let us consider a smooth function such that for fixed
Since one gets from (2.9)
Noticing that and using the Young inequality , we get for some new constant C
Using the inequality
which is due to
we derive easily taking that
where is independent of ℓ. Thus up to a subsequence there exists , such that
From (2.22) one derives that up to a subsequence
Thus, up to a subsequence, a.e on . To see this point one notices that by (2.16) one has
If then
and by (2.15) it follows that
and again due to the strict monotonicity of the function one has a.e on . From this it follows (see for instance [19] lemma 8.3) for a proof that
Now from (2.22) one has
that is
It follows that
and the result, i.e. the strong convergence, follows. □
One can estimate the convergence rate in some situations. Indeed one has:
Letand,be the solutions to (
2.9
), (
2.5
). Then it holds for some constant C independent of ℓwheredenotes the minimum of q and 2.
It follows from the lemmas 2.3 and 2.6 that
If , since , one derives immediately (2.27), i.e.
If one has thanks to Hölder’s inequality
Chosing and taking into account the lemmas 2.1, 2.3 we get for different constants independent of ℓ
(Note that ). Choosing also we are ending up with
Combining this with (2.22) we arrive also to (2.27). □
In the case where one can consider a general f and not only assume that it is in . Indeed one has first:
Suppose that. Ifis defined by (
2.21
) and if α is chosen such thatit holds for some constant C
Since (2.19) is valid for a general f one derives as in (2.23), (2.24)
From this inequality it follows since for various constant C
(In the last inequality we used the Poincaré inequality on ω). This completes the proof of the lemma. □
Then we have:
Suppose that. One has
If one has by (2.16)
Thus from (2.30) one deduces for some constant C
From this it follows that
and (2.33) follows by definition of ρ. In the case when , noting one derives from (2.16), (2.30) for some constant
Thanks to Hölder’s inequality one has as in (2.28)
It follows from (2.10) that
Going back to (2.35) we obtain
Hence
and
The inequality (2.32) follows from these two estimates. □
In the case one can show that exponentially quickly (see [6,15] and also this issue in the next section). Indeed one has:
Suppose that,. It holds for some positive constants C, α
Since one has
This implies that is a -function which is bounded as is (see the lemmas 2.4 and 2.6). Let us set . For consider as in [2]
in (2.19). Taking into account the lemma 2.3 and the fact that we get
Using the Young inequality in this last integral i.e. we get for some new constants
(In the above, we used the fact that and are uniformly bounded independently of ℓ and the Poincaré inequality on the section ω). Choosing it comes
that is to say
It follows from the lemma 2.1 that
The result follows by choosing . □
The last case to address is when , . In this case one can prove:
Suppose that,,. It holds for some positive constants C
Choosing ρ as in (2.21) one has – see (2.16), (2.23)
Recall that . In the two last inequalities we used the fact that and are uniformly bounded and the Poincaré inequality. Arguing as before we have
provided . Thus from (2.43) we derive
Going back to (2.44) one has if
Combining this with (2.45) leads easily to (2.42) since . This completes the proof. □
Some generalisations
Let us denote by a bounded convex domain of containing 0 and by a bounded domain in , . Let us set for
We will denote the points in by
where , . If , are numbers larger than 1 set
Then we define
In the definition above the indices i are running from 1 to m and the indices j from to n. Clearly , are reflexive Banach spaces when equipped with the norms
One denotes by (respectively ) the closure of (respectively ) in these spaces and by the solution to
In the formula above we make the summation convention, i.e. we are summing in i and j. is a continuous linear form on defined as
We would like to sketch some behaviour of when , in particular to show that where is the solution to
Note that by the same arguments as in Section 2 the problems (3.3), (3.5) admit a unique solution. The analogue of lemma 2.1 is the following.
Letbe the solution of (
3.3
) for f given by (
3.4
). There exists a constant C independent of ℓ such that
Let for some . Taking in (3.3) we get with the summation convention in i, j
Using the Poincaré inequality
we derive
Note now that for one has for some constant C independent of ℓ
Thus we get
using the Young inequality . The result follows by choosing . □
With the same proofs we have the analogues of Lemmas 2.2 and 2.4 namely with the summation convention
Similarly if is the solution to (3.3) and the solution to (3.5) and if , then one has
Note that (3.10) allows a perhaps simpler proof of (3.6) where, however, the dependence in f is lost. Indeed taking in (3.10) we get with the summation convention in i and j
Using the Young inequality it comes
and thus for some constant C since
Then we can turn to the generalisation of lemma 2.6. Denote by a smooth function such that
where denotes the gradient of ρ in , i.e. .
We can show:
Let,and,be the solutions to (
3.3
), (
3.5
). Then it holds for some constant C independent of ℓ(denotes the smallest)
From (3.10) taking one derives easily with the summation convention in i and j
Noting that and using Young’s inequality it comes
Recalling our summation in i and the fact that it follows that for some constant C
provided we chose α large enough. Note that at this point we did not use the assumption , . Arguing now like in Lemma 2.6 one can bound by something depending only on to get
This completes the proof of the lemma. □
The convergence of toward is insured for general , by the following result.
Let,. Let,be the solutions to (
3.3
), (
3.5
) respectively. Ifone has for everywhen
The first part of (3.18) follows directly from (3.13). For the second part let us consider a smooth function ρ such that for
Then is a test function for (3.3) and one has
Using the fact that we get by Young’s inequality for some constant C
We assume here that . We know that by (3.11)
and since this bound is independent of ℓ we get
The rest of the proof follows as in Theorem 2.1 since by (3.13) we have for every j
This completes the proof of the theorem. □
We have then an analogue to theorem 2.3 for a general f.
Let,be the solutions to (
3.3
), (
3.5
). Suppose thatThen there exists a constant C such thatis as in Lemma
3.2
.
Going back to (3.16) one has if
Using the Poincaré inequality we get
If one has
and thus for some constant
If one has (see the theorem 2.3)
Thus from (3.21) we derive replacing by p and by q
The first sum is for i such that , the second one for the i’s such that . Using the Young inequality with ϵ we get
Choosing ϵ small enough we get
Coming back to our notation in , (3.19) follows. This completes the proof of he theorem. □
We suppose that,. In addition we assume thatThen there exists constants C, α independent of ℓ such thatNote that when,is only assumed to be greater than 1 and that theare not necessarily distinct as the.
For we denote by a smooth function satisfying
where C is some positive constant. Taking as test function in (3.10) we get
where we have set . Let us define A as
Using the lemma 2.3, (3.32) and the Poincaré inequality on the section of the domain one deduces from (3.31)
It follows that
Denote by the integer part of . Setting and iterating this formula times starting from we obtain easily taking into account the inequality
To evaluate this last integral one relies on the lemma 3.1. Indeed using the lemma 2.3 one has
Using again the formula one derives for some constant
Since is independent of it follows from (3.6) that
and from (3.35) one derives
This leads to (3.29) provided we chose . □
In the case where one can show the following.
We suppose thatand,. In addition we assume thatThen there exists constants C, α independent of ℓ such that
As in Theorem 3.3 we derive (3.31) that is
where . One claims that for some constant C independent of ℓ one has
Then, we derive that
Recalling the notation (3.32), (3.33) follows easily and the rest of the proof as well.
To prove (3.40), suppose that is contained in the strip
for some positive s (recall that is supposed to be bounded in ). Then set
One finds easily since that
If denotes the -norm of f setting
one has (see (3.3))
Using in the weak formulation one deduces easily that
Since , (3.40) follows easily. This completes the proof of the theorem. □
One could try to mix assumptions of the type of Theorem 3.2 and 3.4 however it will make the result regarding the speed of convergence messy, the convergence being insured by the theorem 3.1 for the ’s large enough. In the case of theorems 3.3, 3.4 one can take advantage of the exponential speed of convergence to get existence results in unbounded domains in the spirit of [7,9].
The operators that we have considered here are the sum of p-Laplacians in one dimension. One can consider also operators sums of p-Laplacians in larger dimensions. For instance, with the notation of this section, if is the weak solution to
one can show if , using the technique of theorem 3.3, that converges exponentially quickly toward the solution to.
( denotes the divergence in or ). Similarly one can consider operators sums of p-Laplacians of different dimensions i.e. problems of the type
where denotes some subset of the coordinates, and develop results similar to the ones of this note. The case of the sum of n-dimensional p-Laplacians was considered in [8].
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