Abstract
CCS(h,k) is the CCS subcalculus which can use at most h constants and k actions. We show that CCS(25,12) is Turing-complete by simulating Neary and Woods’ universal Turing machine with 15 states and 2 symbols.
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CCS(h,k) is the CCS subcalculus which can use at most h constants and k actions. We show that CCS(25,12) is Turing-complete by simulating Neary and Woods’ universal Turing machine with 15 states and 2 symbols.