In this paper, we study, for the first time, the nonexistence of solutions to systems of parabolic differential inequalities in 2D exterior domains with Dirichlet and Neumann boundary conditions. Our obtained results complete those derived recently by Yuhua Sun [Nonexistence results for systems of elliptic and parabolic differential inequalities in exterior domains of , Pacific Journal of Mathematics. 293(1) (2018) 245–256] in the N-dimensional case, , under Dirichlet boundary condition.
In this paper, we consider the systems of parabolic differential inequalities
and
where is the closed unit ball in , and is the outward (relative to ) unit normal on . Problems (1.1) and (1.2) are investigated under the assumptions:
We are concerned with the nonexistence of global weak solutions to the considered systems. To the best of our knowledge, this work is the first in which the nonexistence of solutions is discussed for systems (1.1) and (1.2) in the two dimensional case.
Let us provide some motivations for studying problems of the form (1.1) and (1.2). In his famous paper [4], Fujita studied the problem
He proved that
If and , then (1.3) admits no global positive solution.
If and is smaller than a small Gaussian, then (1.3) admits global solutions.
Later, it was shown in [1,5] that (i) holds true for . The real number is said to be critical in the sense of Fujita. In [2], Bandle and Levine studied the exterior Dirichlet problem
where D is a bounded nonempty domain in , . They proved that the critical exponent for (1.4) is still . In [9], Zhang studied the Dirichlet exterior problem (1.4) under the Dirichlet boundary condition
where . He proved that the critical exponent in this case passes from to a bigger value , where . In [6], using the test function method [7], Laptev studied the problem
where , , and . To be more precise, a more general problem was considered in [6], which includes (1.5) as a special case. It was shown that, if
then (1.5) has no nontrivial global weak solution. Very recently, Sun [8] studied the system of parabolic differential inequalities
where D is a bounded Lipschitz domain in , , containing the origin, and , , . He proved the following interesting result: Assume that . If
then (1.6) admits no positive solution. The used approach in [8] is based on an idea of Zhang [9], which consists to show that the -norm and -norm of the solutions blow-up in a certain selected and fixed region. Note that this method, as it was mentioned in [3], is limited to the N-dimensional case, where . Moreover, its application to the Dirichlet case needs the use of the maximum principle.
Motivated by the above cited works, the nonexistence of global weak solutions to (1.1) and (1.2), in the case , is investigated in this paper. Our method is based on a test function approach with a judicious choice of the test function. Moreover, our technique doesn’t require the use of the maximum principle.
Before stating the main results of this paper, let us give the definitions of solutions to (1.1) and (1.2).
We say that is a global weak solution to (1.1), if
and
for every non-negative function satisfying
;
, , in ;
, ;
, .
We say that is a global weak solution to (1.2), if
and
for every non-negative function satisfying
;
in ;
, ;
, .
Our first main result is given by the following theorem.
Let,and. Suppose thatThen for everyand, (
1.1
) admits no global weak solution.
Let us consider the Dirichlet exterior problem
where , , and . From Theorem 1.3, we deduce that for all , (1.11) admits no global weak solution.
Our next main result is given by the following theorem.
Let,and. Suppose thatThen for everyand, (
1.2
) admits no global weak solution.
Let us consider the Neumann exterior problem
where , , and . From Theorem 1.5, we deduce that for all , (1.12) admits no global weak solution.
The rest of the paper is organized as follows. In Section 2, we provide some preliminary estimates. In Section 3, we prove Theorem 1.3. In Section 4, we prove Theorem 1.5. Finally, some open questions are proposed in Section 5.
Preliminary estimates
Let us denote by H the harmonic function in given by
The following result is immediate.
We have
Next, let be a function satisfying
Given , we introduce the functions
and
where
For T large enough, the functiongiven by (
2.2
) satisfies conditions (i)-(iv) of Definition
1.1
.
It is clear that , and satisfies (i). Moreover, by (2.1) and (2.5), we have
Next, for , we have
where is the scalar product in . On the other hand, for , using Lemma 2.1, we have
Therefore,
Observe that
and
Hence, (ii) is satisfied. Note that by (2.4), we have
which proves that (iii) is satisfied. Finally, by the definition of the function Φ, we have
which proves that (iv) is satisfied with . □
Similarly, we have
For T large enough, the functiongiven by (
2.3
) satisfies conditions (i)-(iv) of Definition
1.2
.
Using Lemma 2.1 and the fact that in , we obtain the following identity.
We have
Further, we shall prove some estimates that will be used later. Using Lemma 2.4, the following estimate holds.
We have
Using Lemma 2.5 and the inequality
we obtain the following estimate.
Let. For all, we havewhere.
Further, let
Letand. We haveand
Using (2.2), we have
which yields
On the other hand, using (2.5) and the definition of Φ, for T large enough, we obtain
which yields
Further, using (2.4), after simplification, we get
Next, combining (2.10), (2.11) and (2.12), (2.8) follows.
Now, we shall prove (2.9). Using (2.3), we have
which yields
On the other hand, using (2.6) and the definition of Φ, for T large enough, we obtain
Next, combining (2.12), (2.13) and (2.14), (2.9) follows. □
Letand. We haveand
Using (2.2), we have
which yields
On the other hand, it can be easily seen that
Further, using Lemma 2.6 and (2.5), we obtain
for all . Hence, we obtain
where
and
Next, we have to estimate and . Using the definition of Φ, for T large enough, we have
as . On the other hand, for , we have
where
Therefore,
for . Hence, combining (2.20) with (2.21), we obtain
Further, we have
as . Note that for , we have
Therefore,
for . Then, combining (2.23) with (2.24), we get
Next, using (2.17), (2.18), (2.19), (2.22) and (2.25), we obtain (2.15).
Now, we shall prove (2.16). Using (2.3), we have
which yields
Using (2.6), for T large enough, we have
which from (2.21) yields
Combining (2.18), (2.26) and (2.27), (2.16) follows. □
In this section, we prove Theorem 1.3. We argue by contradiction by supposing that is a global weak solution to (1.1). Given large enough, taking , where is given by (2.2), using Lemma 2.2, (1.7), (1.8) and condition (iii) of Definition 1.1, we obtain
and
where
and
On the other hand, we have
Further, using (2.7) and the definition of Φ, for T large enough, we have
which yields
for T large enough. Hence, using (2.4), for T large enough, we get
where
Similarly, we have
where
Next, writing
and using Hölder’s inequality with parameters q and , we obtain
Using Lemma 2.7 (2.8), we get
Similarly, we have
Again, writing
and using Hölder’s inequality, we obtain
Using Lemma 2.8 (2.15), we obtain
Similarly, we have
Further, using (3.1), (3.3), (3.4), (3.6) and (3.8), we obtain
Similarly, using (3.2), (3.3), (3.5), (3.7) and (3.9), we obtain
Observe that for , we have
and
Therefore, taking in (3.10) and (3.11), we obtain
and
where and are constants (independent on T). Further, we discuss two cases.
If
In this case, we have . Using (3.12) and (3.13), we obtain
where
and
Using (3.14), we obtain
Substituting (3.17) into the left-hand side of (3.14) and simplifying, we get
Continuing with this process, by iteration, for every integer , we obtain
Next, observe that
Hence, using (3.18), we get
On the other hand, using (3.15) and (3.16), we have
and
Therefore, we can fix large enough, so that
Next, passing to the limit as in (3.19), we obtain
which contradicts (3.14), since (3.14) implies that
If
In this case, we have . Therefore, by arguing with a similar manner as with , we obtain a contradiction. This proves Theorem 1.3.
In this section, we prove Theorem 1.5. Suppose that is a global weak solution to (1.2). Given large enough, taking , where is given by (2.3), using Lemma 2.3, (1.9), (1.10) and condition (iii) of Definition 1.2, we obtain
and
where
and
Note that we have
Next, for , using (2.3) and the definition of Φ, for T large enough, we have
which yields
where
Similarly, we have
where
Further, using Lemma 2.7 (2.9), Lemma 2.8 (2.16), and a similar argument as that used in the proof of Theorem 1.3, we obtain
Combining (4.1), (4.2), (4.3), (4.4), (4.5) and (4.6), we obtain
and
Taking in (4.7) and (4.8), we get
and
where and are constants (independent on T). Next, we discuss two cases.
If
In this case, we have . So, using (4.9), (4.10) and arguing as in the proof of Theorem 1.3, we obtain
where are constants (independent on j) and μ is given by (3.15). Since for any , , we have
fixing so that
and passing to the limit as in (4.11), we obtain
which leads to a contradiction.
If
The proof is similar to that of case 1. Hence, Theorem 1.5 is proved.
Open questions
In this section, two open questions are proposed.
Question 1
It would be interesting to study the critical behavior for the mixed exterior problem
where D is the closed unit ball in , . Note that a judicious choice of the test function is required for studying (5.1).
Question 2
It would be interesting to generalize the obtained results in this paper to general external domains with compact boundary.
Footnotes
Acknowledgements
The authors would like to extend their sincere appreciation to the Deanship of Scientific Research at King Saud University for its funding of this research through the Research Group Project No RGP-237.
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