The motivation for the fractional Laplacian originates from probability and mathematical finance as the infinitesimal generators of stable Lévy processes [6–8] which play an important role in stochastic modelling in applied sciences and in financial mathematics. These operators also arise from mechanics in elasto–statics as Signorini obstacle problem in linear elasticity [10] and also from fluid mechanics as quasi-geostrophic fractional Navier–Stokes equation, see [11]. Apart from its significance in mathematics, the fractional Laplacian appears in theoretical physics in connection to the problem of stability of the matter.
Consider the problem
where Ω is a smooth bounded domain in , , and λ is a parameter. It is well known by the Pohozaev identity [23], that if Ω is star-shaped, there exists no bounded positive non-trivial solution of (1.1) when and . Bisci–Rădulescu [20] proved that if is a sub-linear nonlinearity, then there exists an open interval and a such that for every , (1.1) admits at least two distinct, non-trivial weak solutions in whose -norms are less than κ. In [26], Servadei–Valdinoci studied existence of weak positive solutions of the Brezis–Nirenberg problem for the (1.1) with nonlinearity of the form , with and .
Now we consider the case . The critical exponent for in one dimension is and when the critical exponent is infinity. In one dimension, the quasi-relativistic approach to bounded states of the Schrödinger equation leads to the fractional operator corresponding to , which is also known as the Klein–Gordon square root operator [2–5,17,28]. In the case of , we obtain , which is called the ultra-relativistic operator. In this paper we consider, the following competing power problem
where , and
The main goal of the paper is to existence of solution and the limiting profile of the least energy solution for (1.2) when the parameter .
Define the Sobolev space
and the norm
(Weak and classical solution).
We will call is a weak solution of (1.2) if in I and for every , we have
Moreover, is a classical solution of (1.2) if in I, is defined pointwise for all and (1.2) is satisfied pointwise.
Consider the following Liouville equation
Suppose
and and W is a solution to (1.4) in the sense that
where denotes the Schwartz class function on . Then W is given by
see [12, Theorem 1.8].
In two dimensions, the Dirichlet problem was studied by Ren–Wei [22] in a star-shaped domain Ω for the least energy solution. It was extended to the general two-dimensional domain and a precise asymptotic behavior for the least energy solution was obtained in [1] as . For the half Laplacian, the analogous problem was studied in an interval by Santra [25]. Ambrosio [5] studied the multiplicity and concentration of solutions for a fractional magnetic Schrödinger equation in with exponential critical growth. In [29], the authors studied the non-existence of positive solutions for the problem in Ω with , , and is an unbounded domain.
For the zero Dirichlet boundary condition, a similar type of problem
was studied in [13,14] when and . To our knowledge, there exists no result for the problem (1.2) when the two powers in the non-linearity are competing with each other even in the local case.
For each, there exists a even least energy classical solutionto (
1.2
) which is a decreasing on.
Letand defineasFor any, there exists a subsequence ofwhich converges to W inaswhere W can be expressed asfor some.
For, there exists aindependent of p such thatMoreover,
Existence of positive solutions
By [7], the Green function of in can be written as
where is the regular part of of the Green function. Moreover, for some . Here is the fundamental solution of .
Any weak solution to (
1.2
) is bounded inand hence belongs to.
By the Green function (2.1) we obtain
But and which implies
and
Also we have
This implies that for some which depends on p. Hence by Ros-Oton–Serra [24], . □
There exist a classical mountain pass solution to (
1.2
).
Define and we modify the problem (1.2) to
The associated functional to the problem (2.3); by
Then and any critical point of (2.4) is a weak solution to (1.2). It is easy to show that any solution of (2.3) is non-negative, since if we multiply by and integrate by parts; we obtain . Hence and u is in fact a non-negative solution to (2.3). Since is compactly embedded in for any , satisfies the Palais Smale condition and all the conditions of the mountain pass theorem and hence there exists a mountain pass solution and a mountain pass critical value
where
But since any weak solution of (1.2) is in , is a classical solution to (1.2). □
We define the Nehari manifold
For all
Let p be fixed. First note that
We first claim that . Define . We have , for small and for sufficiently large. Hence is achieved. Also note that implies where
It is easy to see that g is an increasing function of t whenever . Thus there exists a unique t such that . Hence there exist a unique point such that and . This implies that is radially homeomorphic to if we prove that is continuous. In order to do so let in . Then in and in for all and
which proves there exist constants and independent of n such that . By passing to the limit in (2.6) the whole sequence converges as is convergent and hence where which proves our claim.
Next we claim that . It is easy to see that
by (2.5). It is enough to prove that any intersects . Note that for sufficiently small and which implies the required result. □
The mountain pass solution of (
1.2
) is even and decreasing in.
Given a non-negative function , define as the symmetric rearrangement. Consequently, applying the symmetric rearrangement inequality for half Laplacian we have
and for all . This implies , for all non-negative u of . Therefore, if is a solution of (1.2), then is even in I and decreasing in . □
There exists aindependent of p such thatfor sufficiently large p.
Define the Moser function by
satisfying . Note that implies . We have
Using the idea in Parini–Ruf [21] we obtain
Next, we write where
By [21], it follows that for . Furthermore, by [18, Proposition 2.2],
Hence (1.3), yields
and
Furthermore,
We have
Then
and hence there exists a unique such that
and
This implies that
This implies that and cannot converge to and hence we can choose p large such that . As a result for ,
which implies that .
But by (2.8) we have
this implies
Using the estimates of and we obtain
where independent of p. □
The least energy solutionsatisfies
By the Hölder’s inequality we obtain
Since , we obtain
This implies and are uniformly bounded and hence by (2.11) we have is uniformly bounded. □
Moreover, for sufficiently large p,where C is a constant independent of p.
Let 0 be a point of maxima of in I. Then and hence from (1.2) we obtain and hence . Proceeding exactly as Lemma 2.1 and using the Stirling formula,
we obtain for all , holds for some constant independent on p. This implies . □
By Lemma 2.7
Choose such that
Then as . Let . Then defined in (1.7) is a classical solution of
We will show that there exists a subsequence of which converges to for any where W satisfies
for some .
There exist a subsequence ofwhich converges to W asinfor any. In particular,.
Let be independent of p and let be a solution of
Using the strong maximum principle, it follows that . Moreover, as , we obtain for any . Therefore, applying [16, Proposition 1.2], it follows , for some which is independent of p. For , we set . Therefore, is a sequence of functions satisfying
which is uniformly bounded below by 0. Since, by the definition of , . Hence by the Harnack inequality [27, Lemma 2.1], there exists a subsequence which is bounded in . Hence there exists a subsequence of which is locally uniformly bounded. We will show that for any and where R is defined before.
Choose and
with in . Let
Define
Then we obtain
Note that for any there exists such that
Using the fact is uniformly bounded and for , we obtain
As before, we define . Then is 1/2-harmonic in hence by [9] we have for any
Hence we have
This implies is uniformly δ-Hölder continuous in . Hence . Using the Arzela–Ascoli theorem, we obtain as in for every . As is locally uniformly bounded, there exists a constant independent of p such that
Now we claim that
for some constant independent of p. From (2.13) we have in and . Hence we obtain
Hence
Note that when and we obtain
This proves the claim. By the Fatou’s lemma
Now we claim that
for any . Note that pointwise as and is locally uniformly bounded. Any satisfies
Hence
is uniformly bounded by an integrable function. By the dominated convergence theorem we obtain (2.18). Furthermore, as is a classical solution of (2.13), it is a distributional solution hence
Using (2.18), we can pass through the limit in above expression to obtain
where
along a subsequence. Since , exists and the formulation is valid
In order to check the validity of (1.5), we need to show that (2.19) holds true even for every . Note that is dense in , for any there exists a sequence such that . But by [19] (Lemma 20.8), there exists a uniform constant such that
Again by the application of the dominated convergence theorem, we have
Moreover, as as , we obtain by the Fatou’s Lemma and Lemma 2.6
Hence we have
for some . □
We have.
We prove by contradiction. If possible, let
along a subsequence. Then W satisfies
The solution to (2.21) is given by for some see [15]. But implies . This implies but as we have which implies . Hence in .
Again by the Green function representation (2.1), we obtain,
Thus we have
But by Lemma 2.6 we obtain
We study
Using the definition of we get
Since in , we have
On the other hand, since in we obtain
Here we used the fact and and . Note that by Lemma 2.6 we obtain
By definition of we obtain
and since we obtain
Moreover,
Since ,
and
This implies that
Hence
and we obtain a contradiction to (2.20).
Using [12], it follows that
and
and hence . This completes the lemma. □
The first part follows from Lemma 2.7. Using the Fatou’s lemma and Lemma 2.7, we have
The other side follows from Lemma 2.6. □
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